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Murljashka [212]
3 years ago
12

A manufacturing company has the following fixed monthly costs and unit variable costs: Rent = $2,200 Utilities = $375 Variable c

osts for materials and assembly = $13.25/unit Monthly labor = $750 If its product sells for $24.99 per unit, how many units must it sell in a month to break even? Round your answer to the nearest whole number.
Mathematics
1 answer:
valentinak56 [21]3 years ago
3 0

A manufacturing company has the following fixed monthly costs and unit variable costs:

Rent = $2,200

Utilities = $375

Variable costs for materials and assembly = $13.25/unit

Monthly labor = $750

Given is the product is sold at $24.99 per unit

Let the number of units sold be x

Adding total cost = 2200+375+750=3325

Equation becomes:

3325+13.25x=24.99x

11.74x=3325

x= 283.21

So, rounding it to nearest whole number we get, 283 units.

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Answer:

1 + 72 ÷4 × 2 =10 with brackets it equals 10

1 + (72 ÷ (4 × 2)) =10

Step-by-step explanation:

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3 years ago
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Answer:

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In all hypothesis proof procedure, we must work with the null one, rejecting it or accepting it. If we reject the null hypothesis, it will mean that our principal hypothesis is true.

According to the problem, the null hypothesis must be: H_{o} : u = 100; because it says that 100 is the normal mean that is used.

The alternative hypothesis must be: H_{a} : u > 100; because the question is asking if there's enough evidence to say that they children have a higher IQ than 100.

Then, we must calculate the P-value, which is the probability value that we are gonna use to accept or reject the null hypothesis. This P-value we can calculate it with the formula: Z=\frac{x-u}{\frac{o}{\sqrt{n} } }; where x is the sample mean, u is the hypothetical mean parameter, o is the sample deviation and n is the sample.

Extracting all values from the problem: x = 104.3; u = 100; o = 14 and n = 20.

Applying all values to the formula: Z=\frac{104.3 - 100}{\frac{14}{\sqrt{20} } } = \frac{4.3}{\frac{14}{ 4.5} }=\frac{4.3}{3.1}=1.4

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<em>In this problems, if the P-value is more than the level of significance, the null hypothesis is accepted. If the P-value is less than the level of significance the null hypothesis is rejected.</em>

Therefore, there is no enough evidence to say that the sample children have higher IQs, because the P-value is higher than the level of significance. (0.735>0.05).

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

Discussion

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Answer:

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