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Vika [28.1K]
3 years ago
14

Helaine graphed the equation 12x – 4y = 3. What was the slope of Helaine’s line?

Mathematics
2 answers:
OlgaM077 [116]3 years ago
5 0
The point slope form of a line is:

y=mx+b where m=slope and b=y-intercept...so

12x-4y=3  solve for y...

4y=12x-3

y=3x-0.75 

So the slope is 3.
quester [9]3 years ago
3 0
The slope is 3
12x-4y=3
-4y=-12x+3
y=3x-3/4
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Find the surface area of the prism formed by the net
Lunna [17]
ANSWER

T.S.A=1960m^2

EXPLANATION

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l=42m

w = 14m

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3 0
3 years ago
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nlexa [21]

Problem 1

x = measure of angle N

2x = measure of angle M, twice as large as N

3(2x) = 6x = measure of angle O, three times as large as M

The three angles add to 180 which is true of any triangle.

M+N+O = 180

x+2x+6x = 180

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x = 20 is the measure of angle N

Use this x value to find that 2x = 2*20 = 40 and 6x = 6*20 = 120 to represent the measures of angles M and O in that order.

<h3>Answers:</h3>
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  • Angle N = 20 degrees
  • Angle O =  120 degrees

====================================================

Problem 2

n = number of sides

S = sum of the interior angles of a polygon with n sides

S = 180(n-2)

2700 = 180(n-2)

n-2 = 2700/180

n-2 = 15

n = 15+2

n = 17

<h3>Answer: 17 sides</h3>

====================================================

Problem 3

x = smaller acute angle

3x = larger acute angle, three times as large

For any right triangle, the two acute angles always add to 90.

x+3x = 90

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x = 90/4

x = 22.5

This leads to 3x = 3*22.5 = 67.5

<h3>Answers:</h3>
  • Smaller acute angle = 22.5 degrees
  • Larger acute angle = 67.5 degrees
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