90 < [( n + n + 2 + n + 4) / 2] < 105
90 < (3n + 6) / 2 < 105
3n + 6 > 180 and 3n + 6 < 210
n > 58 , n < 68
58 < n < 68 answer
Answer: C. 10.2
Step-by-step explanation: because in decimal form 10.19803902 to the nearest is 10.2
Answer:
D) The graph does not represent a one-to-one function because the y-values between 0 to 2 are paired with multiple x-values.
Step-by-step explanation:
Let's find the ordered pairs.
(-4, 4), (-3, 2), (-2, 0), (-1, 0.5), (0, 1), (1, 1.5), (2, 2), (3, 0)
The graph passed through above points.
In the x-coordinates -3, 2 gives the same output. Therefore, the given function is not one-to-one.
Therefore, the answer D)
The graph does not represent a one-to-one function because the y-values between 0 to 2 are paired with multiple x-values.
Hope you will understand the concept.
Thank you.
Hello!
Here are some rules to determine the number of significant figures.
- Numbers that are not zero are significant (45 - all are sigfigs)
- Zeros between non-zero digits are significant (3006 → all are sigfigs)
- Trailing zeros are not significant (0.067 → the first two zeros are not sigfigs)
- Trailing zeros after a decimal point are always significant (1.000 → all are sigfigs)
- Trailing zeros in a whole number are not significant (7800 → the last two zeros are not sigfigs)
- In scientific notation, the exponential digits are not significant, known as place holders (6.02 x 10² → 10² is not a sigfig)
Now, let's find the number of significant figures in each given number.
A). 296.54
Since these digits are all <em>non-zero</em>, there are 5 significant figures.
B). 5003.1
Since the two <em>zeros are between non-zero digits</em>, they are significant figures. Thus, there are 5 significant figures.
C). 360.01
Again, the two zeros are between non-zero digits. There are 5 significant figures.
D). 18.3
All of these digits are non-zero, hence, there are 3 significant figures.
Therefore, expression D has the fewest number of significant figures being 3.
