Answer: The cumulative frequency of club members who exercise publicly for six or fewer times per week = 38
Step-by-step explanation:
The given results of the survey:
0 visits per week: 13
1-3 visits per week: 17
4-6 visits per week: 8
7 or more visits per week: 17
The cumulative frequency of club members who exercise publicly for six or fewer times per week = Frequency for 0 visits + Frequency for 1-3 visits per week + Frequency for 4-6 visits per week
= 13+17+8
=38
Hence, the cumulative frequency of club members who exercise publicly for six or fewer times per week = 38
Answer:
I would believe 45
Step-by-step explanation:
if portioned correctly in scoops your dividing each flavor by portions not cones
Answer:
a) P(75 < x < 80 ) = 0.2088
b) The probability that average height of all humans less than 65
P( X < 65 ) = 0.0495
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
Given mean of the Population = 72
Given variance of the Population = 18 inches.
Standard deviation of the Population = √18 = 4.242
Let 'x' be the random variable in Normal distribution
a)
Given X₁ = 75
Given X₂= 80
The probability that average height of all humans between 75 and 80
= | A ( 1.885) - A( 0.70721|
= 0.4699 - 0.2611
= 0.2088
P(75 < x < 80 ) = 0.2088
b)
<u><em>Step(ii)</em></u>:-
Given X₁ = 65
The probability that average height of all humans less than 65
P( X < 65 ) = P( Z < - 1.650 )
= 1 - P( Z > 1.650)
= 1 - ( 0.5 + A (1.650))
= 0.5 - A( 1.65)
= 0.5 - 0.4505
= 0.0495
The probability that average height of all humans less than 65
P( X < 65 ) = 0.0495
Answer:
negative multiples of 3 less than -3
Step-by-step explanation:
if m <9, then
m ={8,7,6,5,4,3,2,1,0,-1,-2,....,..........}
And |6m-55|
So is said that,
when, m= 8
6(8)-55=-6
when, m=7
6(7)-54=-12
when, m = 6
6(6)-54=-18
Since the trend is negative multiples of 3 less than -3
this is my answer