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Dimas [21]
3 years ago
15

Which triangle had hypotenuse BF​

Mathematics
2 answers:
Dafna11 [192]3 years ago
5 0

Answer:

triangle GBF and GFC

Step-by-step explanation:

The shape above is a cube and it has six faces. Each face is square in shape. Each square has diagonals.

Considering square BCGF, the square can be divided into two right angle triangle GBF and GFC using a diagonal line cutting across point GC.

According to triangle GBF formed, the diagonal BF serves as the hypotenuse of the triangle because hypotenuse is known to be the longest side of a triangle .

therefore the triangle that had hypotenuse as BF is triangle GBF and GFC

patriot [66]3 years ago
3 0

Answer:

BGF and BCF

Step-by-step explanation:

those two triangles have BF as the hypotenuse

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The train to Sun City travels 150 miles per hour. How long will a trip take if Sun City is 525 miles away?
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525 divided by 150 is 3.5

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answer is b
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Answer :

Step by Step Explanation :
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3 years ago
A researcher compares the effectiveness of two different instructional methods for teaching electronics. A sample of 138 student
yan [13]

Answer:

The 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the difference between population means is:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

The information provided is as follows:

n_{1}= 138\\n_{2}=156\\\bar x_{1}=61\\\bar x_{2}=64.6\\\sigma_{1}=18.53\\\sigma_{2}=13.43

The critical value of <em>z</em> for 98% confidence level is,

z_{\alpha/2}=z_{0.02/2}=2.326

Compute the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 as follows:

CI=(\bar x_{1}-\bar x_{2})\pm z_{\alpha/2}\times \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}

     =(61-64.6)\pm 2.326\times\sqrt{\frac{(18.53)^{2}}{138}+\frac{(13.43)^{2}}{156}}\\\\=-3.6\pm 4.4404\\\\=(-8.0404, 0.8404)\\\\\approx (-8.04, 0.84)

Thus, the 98% confidence interval for the true difference between testing averages for students using Method 1 and students using Method 2 is (-8.04, 0.84).

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Wittaler [7]
By  <span>(x + 5/x^2 + 9x + 20) you apparently meant the following:

         x+5
 ----------------------
   x^2 + 9x + 20

and by 

</span><span>(x^2-16/x-4)
                                       x^2-16
you apparently meant ---------------
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Please use additional parentheses for clarity.

Dividing,

</span>         x+5                   (x-4)(x+4)
 ----------------------  *  ---------------
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Now, x^2 + 9x + 20 factors into   (x+4)(x+5), so what we have now is

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3 years ago
How to write 84 divided into sevenths
Rudik [331]
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In the end, the answer would be 12. 
6 0
3 years ago
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