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2 years ago

PLEASE HELP ME ASAP! DUE TODAY! (functions) (brainliest)

Mathematics

1 answer:

Tems11 [23]2 years ago

6 0

Answer:

how did you get the graph on here

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Cedric's basketball team scored fewer than 76 points in their last game. Which of the following inequalities represents the numb

Lelechka [254]

Answer: $n$

Step-by-step explanation:

Although you did not provide the inequalities, the only inequality that can represent the number of points Cedric's basketball team scored in their last game is the one shown below:

Let's call the number of points Cedric's basketball team scored in their last game: $n$ .

You know that Cedric's basketball team scored fewer than 76 points in their last game. "Fewer than" means "less than", which is represented with the symbol < .

Therefore, you can represent the number of points Cedric's basketball team scored in their last game with the following inequality:

$n$

8 0

3 years ago

Select the correct answer.

adelina 88 [10]

Answer:

$\frac{5}{4} x - 2 = \frac{3}{2} x-4$

Step-by-step explanation:

$\frac{5}{2} x +\frac{7}{2} =\frac{3}{4} x+14 \\\frac{5}{2}x -\frac{3}{4} x=14-\frac{7}{2} \\\frac{10-3}{4} x =\frac{28-7}{2} \\\frac{7}{4} x =\frac{21}{2} \\x = \frac{21}{2} * \frac{4}{7} = 6 \\$

$\frac{5}{4} x -9 = \frac{3}{2} x-12 \\\frac{5}{4} x - \frac{3}{2} x= -12 + 9 \\\frac{5-6}{4} x = -3 \\\frac{-1}{4} x = -3 \\x = -3 * -4 \\x = 12$

$\frac{5}{4} x-2=\frac{3}{2} x-4 \\\frac{5}{4} x-\frac{3}{2} x=-4+2 \\\frac{5-6}{4}x=-2 \\\frac{-1}{4} x = -2 \\x = -2 * -4 \\x = 8$

$\frac{5}{2} x -7 = \frac{3}{4} x+14 \\\frac{5}{2}x -\frac{3}{4} x=14+7 \\\frac{10-3}{4} x =21 \\\frac{7}{4} x =21 \\x = 21 * \frac{4}{7} = 12 \\$

You could also replace x for 8 in every equation and see if both sides give the same answer

8 0

2 years ago

Hey I need help on a question real fast the question is if three equals B times seven then seven times be equals what

bonufazy [111]

Answer would be 14b.

3 0

2 years ago

What is the equation in vertex

jok3333 [9.3K]

$\bf ~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{ope ns~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}$

$\bf \stackrel{\textit{vertex}}{(3,-2)}~~ \begin{cases} h = 3\\ k = -2 \end{cases}\implies y=a(x-3)^2-2 \\\\\\ \stackrel{\textit{passes through}}{(5,-1)}~~ \begin{cases} x=5\\ y= -1 \end{cases}\implies -1=a(5-3)^2-2\implies 1=a(2)^2 \\\\\\ 1=4a\implies \cfrac{1}{4}=a~\hfill \boxed{y=\cfrac{1}{4}(x-3)^2-2}$

5 0

2 years ago

Read 2 more answers

Your favorite team is in the World Series. You have assigned a probability of 63% that they will win the championship. Past reco

frozen [14]

Answer:

0.3950

Step-by-step explanation:

Any team team will win the championship with probability 63% that is

P(W)=0.63

when teams win the championship, they win the first game of the series 72% of the time that is

P(F|W)=0.72

When they lose the championship, they win the first game 27% of the time.

P(F|W')=0.27

The probability that they will win the World Series when the first game is over and your team has lost that is

P(W|F')

Now, By Bayes theorem

$\begin{array}{l}P\left(W | F^{\prime}\right)=\frac{P\left(F^{\prime} | W\right) P(W)}{P\left(F^{\prime} | W\right) P(W)+P\left(F^{\prime} | W^{\prime}\right) P\left(W^{\prime}\right)} \\\quad=\frac{[1-P(F | W)] P(W)}{[1-P(F | W)] P(W)+\left[1-P\left(F | W^{\prime}\right)\right][1-P(W)]} \\\quad=\frac{[1-0.72] \times 0.63}{[1-0.72] \times 0.63+[1-0.27][1-0.63]} \\\quad=\frac{0.28\times 0.63}{0.28\times 0.63+0.73 \times 0.37} \\=0.3950\end{array}$

5 0

2 years ago