Lol I was looking for help for this question but I couldn't find it so I had to figure it out my self and the answer is 40
The graph is shown in the attached image.
Answer:
A) attached below
B) 0.61
C) 0.47
Step-by-step explanation:
Given data:
Total number of lizards infected = 38
Of the 15 species B lizards 40% survived
For specie C one more survived than died
Out of the 24 lizards that died 1/3 were species A
<u>A) contingency table </u>
attached below
<u>B) Determine the proportion of these lizards in this study that were either specie A or Specie B </u>
P ( A or B ) = ( 8 + 15 ) / 38 = 0.605 ≈ 0.61
<u>C) determine the probability that specie C lizard did not study </u>
P ( not surviving | C ) = 7 / 15 = 0.466 ≈ 0.47
Distribute and combine like-terms!
-4x + 12x - 2x - 2
6x - 2