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2 years ago

Erica has twice as many magazines as puzzle games. She has 30 of both in total. Write an

Mathematics

2 answers:

MArishka [77]2 years ago

5 0

She has 20 magazines and 10 puzzle games

m=magazines (20)
p=puzzle games (10)

m + p=30
m =2p
2p+p=30

kicyunya [14]2 years ago

4 0

Answer:

Well go ask Erica how many magazines she has.

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What is the reflection image of P(0, 0) after two reflections, first across x = 4 and then across y = -3?

jek_recluse [69]

Answer:

The reflection image of P(0, 0) after two reflections is (8,-6)

Step-by-step explanation:

step 1

Find the coordinates of point P after reflection across x=4

we know that

The distance from point P to the line x=4 is equal to 4 units

(0,0) -----> (4+4,0) ----> (8,0)

The reflection image of P is (8,0)

step 2

Find the coordinates of point (8,0) after reflection across y=-3

The distance from point (8,0) to the line y=-3 is equal to 3 units

(8,0) -----> (8,-3-3) ----> (8,-6)

3 0

3 years ago

Evaluate 5! + 2!. 60 122 5,040

ludmilkaskok [199]

! Means starting from that number multiply by every number down to 1.

5!= 5•4•3•2•1 = 20•6=120

2!= 2•1=2

120+2=122 :)

8 0

3 years ago

A road repair crew spread 7/8 of a ton of gravel evenly over 7 feet of road. How many tons of gravel did they spread on each foo

Alex

7/8 duh it there u just have to read it nicely

5 0

3 years ago

Evaluate Combination (6,6)

andrew11 [14]

Answer:

$nCx = \frac{n!}{x! (n-x)!}$

On this case n =6 and x =6 we got:

$6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1$

Step-by-step explanation:

The utility for the combination formula is in order to find the number of ways to order a set of elements

For this case we want to find the following expression:

$6C6$

And the general formula for combination is given by:

$nCx = \frac{n!}{x! (n-x)!}$

On this case n =6 and x =6 we got:

$6C6 = \frac{6!}{6! (6-6)!} = \frac{6!}{6! 0!}= \frac{6!}{6!}=1$

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3 years ago

in Youngstown, the population reached 4420 people in 1993. in 1998 the population was 5600 residents. what was the population in

Julli [10]

5600 - 4420 = 1180....so there is a difference of 1180 in a period of (1998 - 1993) = 5 yrs.

1180/5 = 236 people per yr

so in 1998 the population was 5600.....in 2000 (2 yrs later) the population would be : 5600 + 236(2) = 5600 + 472 = 6072 <==

4 0

3 years ago