1500 pounds since a ton I 2000 just multiply it by 3/4
The total charge would be $445.
Hope this helps!!
Answer:
x+y+2=-5 -2x-y+2=-1 x-2y-2=0 solve algebraically
x+y+2=-5 equation 1
-2x-y+2=-1 equation 2
x-2y-2=0 equation 3
Add equation 1 + 2+ 3
x+y+2=-5 + -2x-y+2+1 + x-2y-2
x+y+2= -7+2+1-2x+x+y
x+y+2= -4-x+y
x+y+2+4+x-y= 0
2x+6= 0
2x= -6
divide both side by 2
x= -3
from equation 1 insert x
x+y+2=-5
since x=-3
then, -3+2+y= -5
-1+y= -5
y= -5+1
y= -4
Step-by-step explanation:
Because of the symmetry, we can just go from x=0 to x=2 to find the area between
<span>y = x^2 and y = 4 </span>
<span>that area = ∫4-x^2 dx from 0 to 2 </span>
<span>= [4x - (1/3)x^3] from 0 to 2 </span>
<span>= 8 - 8/3 - 0 </span>
<span>= 16/3 </span>
<span>so when y = b </span>
<span>x= √b </span>
<span>and we have the area as </span>
<span>∫(b - x^2) dx from 0 to √b </span>
<span>= [b x - (1/3)x^3] from 0 to √b </span>
<span>= b√b - (1/3)b√b - 0 </span>
<span>(2/3)b√b = 8/3 </span>
<span>b√b =4 </span>
<span>square both sides </span>
<span>b^3 = 16 </span>
<span>b = 16^(1/3) = 2 cuberoot(2) </span>
<span>or appr 2.52</span>
For line B to AC: y - 6 = (1/3)(x - 4); y - 6 = (x/3) - (4/3); 3y - 18 = x - 4, so 3y - x = 14
For line A to BC: y - 6 = (-1)(x - 0); y - 6 = -x, so y + x = 6
Since these lines intersect at one point (the orthocenter), we can use simultaneous equations to solve for x and/or y:
(3y - x = 14) + (y + x = 6) => 4y = 20, y = +5; Substitute this into y + x = 6: 5 + x = 6, x = +1
<span>So the orthocenter is at coordinates (1,5), and the slopes of all three orthocenter lines are above.</span>
