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gayaneshka [121]
3 years ago
13

ramon has a rope that is 25 1/2 feet long. he wants to cut it into 6 pieces that are equal in length. how long will each piece b

e?
Mathematics
1 answer:
choli [55]3 years ago
6 0
4.25. cause you didved 25.5 into 6. cause 25 1/2 turns into 25.5 as a decmail and that the way i got
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The figure is made up of 2 cones and a cylinder. The cones and cylinder have a 4 cm diameter.
Nina [5.8K]
20 cm is the answer good luck
4 0
3 years ago
What is the ratio for 8 and 12
Vitek1552 [10]
It can be 8:12 or as a fraction it’s 8/12
5 0
3 years ago
The null and alternative hypotheses are given. Determine whether the hypothesis test is​ left-tailed, right-tailed, or​ two-tail
WINSTONCH [101]

Answer:    Two-tailed test.

Population mean is the parameter which is tested.

Step-by-step explanation:

Given :   H_0: \mu=105

H_1:\mu\neq105

We know that , the alternative hypothesis (H_1) indicates kind of the hypothesis test we need to perform whether ​left-tailed, right-tailed, or​ two-tailed.

Here, the alternative hypothesis (H_1) is two-tailed, so the hypothesis test is a two-tailed test.

Also, the parameter present in the hypothesis is \mu which is a symbol to represent the population mean.

Thus , Population mean is the parameter which is tested.

8 0
2 years ago
How does the graph of f(x)=3lx+2l+4 relate to its parent function?
Sergeeva-Olga [200]
\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}

\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\qquad  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\
\end{array}

\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{  D}}\\
\qquad if\ {{  D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}
\end{array}

now, with that template above in mind, let's see this one

\bf parent\implies f(x)=|x|
\\\\\\
\begin{array}{lllcclll}
f(x)=&3|&1x&+2|&+4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}


A=3, B=1,  shrunk by AB or 3 units, about 1/3
C=2,          horizontal shift by C/B or 2/1 or just 2, to the left
D=4,          vertical shift upwards of 4 units

check the picture below

7 0
2 years ago
Solve for x.<br><br> X = ____?
I am Lyosha [343]
Set up a proportion
EA / EB = ED/ EC
16 / (5x + 2 + 16) = 12 / (12 + 24)
16/(5x + 18) = 12 / 36 Cross multiply
16 * 36 = (4x + 18)*12 Remove the brackets
576 = 48x + 216 Subtract 216 from both sides.
360 = 48x Divide by 48
360/48 = x
7.5 = x

8 0
2 years ago
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