WILL NAME BRAINLYEST AND 33 POINTS
1 answer:
Answer:
Shown below
Step-by-step explanation:
5³ ... 5·5·5 ... 125
6² ... 6·6 ... 36
7³ ... 7·7·7 ... 343
... 9 ... 9
... 2·2·2·2 ... 64
4³ ... 4·4·4 ... 64
... 3·3·3·3 ... 81
3³ ... 3·3·3 ... 27
... 2·2·2·2·2 ... 32
... 4·4·4·4 ... 256
... 8 ... 8
2²·5² or 10² ... 2·2·5·5 ... 100
·6² or 54² ... 3·3·3·3·6·6 ... 2916
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Answer:
The probability that the cost for someone's dog is higher than for the cat is 33.2%.
Step-by-step explanation:
With the data given, we know that the difference in cost of medical care of dogs and cats have a normal distribution with μ=-20 and σ=46.
To know the probability of the cost for the dog is higher than the cat, we have to calculate the probability of P(d>0).
Then we have to calculate z, and look up in a standarized normal distribution table.
Calculate z:
The probability of the difference being higher than 0, we have:
We can say that the probability that the cost for someone's dog is higher than for the cat is 33.2%.