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Grace [21]
2 years ago
6

Determine if the data comes from a linear function or an exponential function. Then, enter

Mathematics
1 answer:
svet-max [94.6K]2 years ago
8 0

1.  The data is not linear.  There's not a constant difference between the f(x) values.  (AKA there's not a fixed slope between the data points)

2. The data is exponential, because there's a consistent ratio in the f(x) values:

     189/567 = 1/3

     63/189 = 1/3

     21/63 = 1/3

     7/21 = 1/3

Each new y-value (aka f(x)-value) is 1/3 the previous value.

Also, f(0)=567.

If we put that together, we have f(x) = 567 (1/3)^x.

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Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
Find the median of the following data 20,14,6,25,18,13,19,10,9,12
vivado [14]

Step-by-step explanation:

1. Arrange all the numbers in ascending order.

2. Since there are 10 numbers, there will be 2 numbers in the middle, add those two middle numbers and divide by 2.

3. The result is your answer.

5 0
3 years ago
Read 2 more answers
If r(x) = 3x - 1 and s(x) = 2x + 1, which expression is equivalent to (r/s)(6)?
zavuch27 [327]

Answer:

17/13

Step-by-step explanation:

r(6) = 3(6) - 1 = 17 and s(6) = 2(6) + 1 = 13.

Then (r/s)(6) = 17/13.

4 0
3 years ago
Can you please help me with the whole table
Bad White [126]
44,000
38,720
34,073.60
29,984.77
26,386.60
7 0
2 years ago
Customers of a phone company can choose between two service plans for long distance calls. The first plan has no monthly fee but
alex41 [277]

Answer:

380

Step-by-step explanation:

.20x = 19 + .15x

.05x = 19

x = 380

5 0
2 years ago
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