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N76 [4]
3 years ago
13

Muhares, which uses a process-costing system, adds material at the beginning of production and incurs conversion cost evenly thr

oughout manufacturing. The following selected information was taken from the company's accounting records:
Total equivalent units of materials: 8,000
Total equivalent units of conversion: 7,400
Units started and completed during the period: 6,500
On the basis of this information, the ending work-in-process inventory's stage of completion is:__________
a) 80%.
b) 70%.
c) 60%.
d) 40%.
e) some other percentage not listed above.
Business
1 answer:
Lapatulllka [165]3 years ago
4 0

Answer:

c). 60%

Explanation:

Calculation for what the ending work-in-process inventory's stage of completion is:

First step is to calculate the Units in process

Units in process = 8,000 - 6,500

Units in process= 1,500 units

Second step is to calculate Equivalent units of conversion for in process

Equivalent units of conversion for in process = 7,400 - 6,500

Equivalent units of conversion for in process= 900

Now let calculate the ending work-in-process inventory's stage of completion

Ending work-in-process inventory's stage of completion=900 / 1,500

Ending work-in-process inventory's stage of completion= 0.60*100

Ending work-in-process inventory's stage of completion=60%

Therefore the the ending work-in-process inventory's stage of completion is:60%

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Which of the following is the amount of money the business has earned after paying income taxes?
Gwar [14]

Answer:

Net income is the amount of money the business has earned after paying taxes

4 0
3 years ago
On January 1, 2017, Marin Company purchased 12% bonds, having a maturity value of $320,000, for $344,260.74. The bonds provide t
kap26 [50]

Answer and Explanation:

The Journal entry is shown below:-

1. Debt Investment Dr, $344,260.74  

       To Cash $344,260.74

(Being cash paid is recorded)

2. Interest Receivable Dr, $38,400  

       To Debt Investment $3,973.93

        To Interest Revenue $34,426.07

(Being interest received is recorded)  

Fair Value Adjustment  Dr, $1,713.19  ($342,000 -$340,286.81)

     To Unrealized Holding Gain or Loss - Equity $1,713.19

(Being fair value adjustment is recorded)

3. Unrealized Holding Gain or Loss - Equity  $7928.68

($335,915.49 - $329,700 + $1,713.19)

       To Fair Value Adjustment 7,928.68

(Being unrealized loss or gain is recorded)

Working note

 Book value of    Interest         Interest     Amortization  Book value

  debt beginning  Revenue   Receivable   (d = c - d)       of debt

        (a)                    b=(a × 10%)      c                                    at the end

                                             ($320,000 × 12%)                   (e - d)

$344,260.74      $34,426.07    $38,400      $3,973.93  $340,286.81

$340,286.81      $34,028.68    $38,400       $4,371.32   $335,915.49

8 0
3 years ago
A company is considering buying a new piece of machinery. A 10% interest rate will be used in the computations. Two models of th
JulsSmile [24]

Answer:

Machine I

capitalized cost:  230,271.28

EAC: $ 27,047.58

Machine II

EAC:  $ 27,377.930  

As Machine I cost per year is lower it is better to purchase that one.

Annual deposits to purchase Machine I in 20 years: $ 1,396.770  

return of machine I with savings of 28,000 per year: 10.51%

Explanation:

WE calculate the present worth of each machine and then calculate the equivalent annual cost:

MACHINE 1

Operating cost:

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\  

C 18,000

time 20

rate 0.1

18000 \times \frac{1-(1+0.1)^{-20} }{0.1} = PV\\  

PV $153,244.1470  

Salvage value:

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity  $20,000.0000  

time   20.00  

rate  0.1

\frac{20000}{(1 + 0.1)^{20} } = PV  

PV   2,972.87  

Total: -80,000 cost - 153,244.15 annual cost + 2,972.87 salvage value:

Total: 230,271.28

PV \div \frac{1-(1+r)^{-time} }{rate} = C\\  

Present worth  $(230,271.28)

time 20

rate 0.1

-230271.28 \div \frac{1-(1+0.1)^{-20} }{0.1} = C\\  

C -$ 27,047.578  

Fund to purchase in 20 years:

FV \div \frac{(1+r)^{time} -1}{rate} = C\\  

FV  $80,000.00  

time 20

rate 0.1

80000 \div \frac{(1+0.1)^{20} -1}{0.1} = C\\  

C  $ 1,396.770  

IF produce a 28,000 savings:

we must solve using a financial calcualtor for the rate at which the capitalized cost equals 28,000

PV \div \frac{1-(1+r)^{-time} }{rate} = C\\  

PV  $230,271.28  

time 20

rate 0.105126197

230271.28 \div \frac{1-(1+0.105126197287798)^{-20} }{0.105126197287798} = C\\  

C  $ 28,000.000  

rate of 0.105126197 = 10.51%

<u>Machine II</u>

100,000 cost

25,000 useful life

15,000 operating cost during 10 years

20,000 for the next 15 years

Present value of the operating cost:

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\  

C 15,000

time 10

rate 0.1

15000 \times \frac{1-(1+0.1)^{-10} }{0.1} = PV\\  

PV $92,168.5066  

C \times \frac{1-(1+r)^{-time} }{rate} = PV\\  

C 20,000

time 15

rate 0.1

20000 \times \frac{1-(1+0.1)^{-15} }{0.1} = PV\\  

PV $152,121.5901  

in the timeline this is at the end of the 10th year we must discount as lump sum for the other ten years:

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity  $152,121.5901  

time   10.00  

rate  0.1

\frac{152121.590126167}{(1 + 0.1)^{10} } = PV  

PV   58,649.46  

salvage value

\frac{Maturity}{(1 + rate)^{time} } = PV  

Maturity  $25,000.0000  

time   25.00  

rate  0.1

\frac{25000}{(1 + 0.1)^{25} } = PV  

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Total cost: 100,000 + 92,168.51 + 58,649.46 - 2,307.40 = $248,510.57

PV \div \frac{1-(1+r)^{-time} }{rate} = C\\  

PV  $248,510.57  

time 25

rate 0.1

248510.57 \div \frac{1-(1+0.1)^{-25} }{0.1} = C\\  

C  $ 27,377.930  

4 0
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Ne4ueva [31]

Answer:

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Explanation:

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6 0
4 years ago
An officer participates in litigation against the CPA firm. This is an example of which type of threat to compliance with which
Shkiper50 [21]

Answer: An officer participates in litigation against the CPA firm. This is an example of Adverse interest.

<u>Explanation:</u>

This is an example of Adverse interest. Adverse here means against the interest of others. This type of interest in mostly found in case of property disputes. Like if a person has illegally occupied someone else's property than his interest in that property will be adverse the interest of the real owner of that property.

Similarly here an officer is participating in legal action against CPA firm,The interest of an officer will be an adverse.

7 0
4 years ago
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