Hello!
To find the amount of energy need to raise the temperature of 125 grams of water from 25.0° C to 35.0° C, we will need to use the formula: q = mcΔt.
In this formula, q is the heat absorbed, m is the mass, c is the specific heat, and Δt is the change in temperature, which is found by final temperature minus the initial temperature.
Firstly, we can find the change in temperature. We are given the initial temperature, which is 25.0° C and the final temperature, which is 35.0° C. It is found by subtract the final temperature from the initial temperature.
35.0° C - 25.0° C = 10.0° C
We are also given the specific heat and the grams of water. With that, we can substitute the given values into the equation and multiply.
q = 125 g × 4.184 J/g °C × 10.0° C
q = 523 J/°C × 10.0° C
q = 5230 J
Therefore, it will take 5230 joules (J) to raise the temperature of the water.
Supplementary angles add up to 180, so
6x+60+90 = 180 and solve for x
6x= 30
x=5
Answer:
A 12.630 bar of chocolate contains 8315 milligrams of sugar
Explanation:
From the basics of conversion, we can find that:
1 gram is equal to 1000 mg
Using cross multiplication, we can find how many milligrams are present in 8.315 grams as follows:
1 gram .............> 1000 mg
8.315 grams ....> ?? mg
amount in milligrams = (8.315*1000) / 1 = 8315 milligrams
Hope this helps :)
Two Half Cell reactions are as,
Reduction: PbO₂ + 2e⁻ → Pb²⁺
As it is acidic medium reaction, so add H⁺ on reactant side as it has more number of oxygen atoms and add H₂O on product side, and balance tehe elements, So,
4 H⁺ + PbO₂ + 2e⁻ → Pb²⁺ + 2 H₂O (1)
Oxidation: I⁻ → I₂ + 1e⁻
Balance Number of elements along with electrons,
2 I⁻ → I₂ + 2e⁻ (2)
Compare eq. 1 and 2,
4 H⁺ + PbO₂ + 2e⁻ → Pb²⁺ + 2 H₂O
2 I⁻ → I₂ + 2e⁻
⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻
PbO₂ + 2 I⁻ + 4 H⁺ → Pb²⁺ + I₂ + 2H₂O
Number of Coefficients = 11
protons and neutrons are in the nucleus electrons surround the atom and i have no idea what positrons are i just know they arent in an atom so your answer is B and C
