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PSYCHO15rus [73]
3 years ago
14

Brian has an object suspended in the air. It has a mass of 100 kg and is 25 meters above the ground. What is the object’s potent

ial energy
Chemistry
2 answers:
MatroZZZ [7]3 years ago
7 0
The answer is 24500 joule
worty [1.4K]3 years ago
5 0

Answer:

P.E = 24500

Explanation:

Potential energy is the energy possessed by a object in a position. An object can store energy as a result of it position. An example is having a ball held upward by a pavement. The stored energy by the ball is known as the potential energy.

Since the object is suspended upward with a height of 25 meters , gravity is involved. Gravitational potential energy is the energy stored by an object as a result of it height.  Gravitational potential energy is dependent by the height which the object is raised and the mass. The higher the height of an object is raised the greater the gravitational potential energy.

The formula for gravitational potential energy is as follows ;

P.E = mass × height ×  gravitational field strength(9.8N/kg)

P.E = mgh

m = 100 kg

height = 25 meters

g = 9.8 N/kg

P.E = 100 × 9.8 × 25

P.E = 24500

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Hydrogen Peroxide, H2O2, in the presence of a catalyst decomposes into water and oxygen gas. How many L of O2 at STP are produce
Korolek [52]

Answer:

There is 11.2 L of O2 produced

Explanation:

<u>Step 1:</u> Data given

Molar mass of H2O2 = 34.01 g/mol

Molar mass of O2 = 32 g/mol

Mass of H2O2 = 34.0 grams

<u>Step 2:</u> The balanced reaction

2H2O2 → 2H2O + O2

<u>Step 3</u>: Calculate number of moles H2O2

Moles H2O2 = Mass H2O2 / Molar mass H2O2

Moles H2O2 = 34 grams / 34.01 g/mol

Moles H2O2 = 1 mol

<u>Step 4: </u>Calculate the number of moles at the equilibrium

Initial number of moles H2O2 = 1 mol

Initial number of mol H2O and O2 = 0 mol

Since the mol ratio H2O2 H2O O2 is 2:2:1

There will react x mol of H2O2; X mol of H2O and 0.5 x mol of O2

At the equilibrium, H2O2 has (1-x) mol. Since it's decomposed into H2O and O2, we know x =1 mol

At the equilibrium, there is 1 mol H2O and 0.5 mol O2

Under STP, 1 mol of gas has a volume of 22.4 L

This means 0.5 moles of O2 has a volume of 22.4*0.5 = 11.2 L

There is 11.2 L of O2 produced

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