everything describes physical traits ect. and 3 explains reactions with a different substance so 3
The specific heat capacity of unknown substance is 1.333 g/j/°c
<u><em> calculation</em></u>
Specific heat capacity is calculated using Q= MCΔT formula
where;
Q(heat)= 800 j
M(mass) = 30 g
C(specific heat capacity) =?
ΔT( change in temperature) = 40°c - 20°c = 20°c
make C the subject of the formula by diving both side of the formula by MΔT
C is therefore = Q/MΔT
800j / 30 g x 20°c = 1.333 j/g/°c
Answer:
you need to use the of the five to the report to the report that there are two different and the other two are the same limited as the or the two of the 8
Explanation:
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