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weeeeeb [17]
3 years ago
13

Match the scientist to his contribution to the atomic theory - Thomson - Rutherford - Bohr A. Electron energy levels B. Nucleus

C. Electrons
Chemistry
1 answer:
N76 [4]3 years ago
6 0

Answer: Thomson - C

Rutherford - B

Bohr - A

Explanation: I just took the quiz

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Choose the weakest acid?. 1. H2Se, H2O, H2Te, or H2S. 2. H2SeO4, H2SeO3, H2SO3, or H2SO4. 3. HClO3, H2Se, HBr, HNO4
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The weakest acid in each sequence is;

A.H2Te
B.H2SeO4
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What is the relative atomic mass of thallium?
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2 years ago
A 19.0 g piece of metal is heated to 99.0 °C and then placed in 150 mL of water at 21°C. The temperature of the water rose to 23
Anna35 [415]

Answer:

0.8696\ \text{J/g}^{\circ}\text{C}

Explanation:

m_m = Mass of metal = 19 g

c_m = Specific heat of the metal

\Delta T_m = Temperature difference of the metal = 99-23=76^{\circ}\text{C}

V = Volume of water = 150 mL = 150\ \text{cm}^3

\rho = Density of water = 1\ \text{g/cm}^3

c_w = Specific heat of the water = 4.186 J/g°C

\Delta T_w = Temperature difference of the water = 23-21=2^{\circ}\text{C}

Mass of water

m_w= \rho V\\\Rightarrow m_w=1\times 150\\\Rightarrow m_w=150\ \text{g}

Heat lost will be equal to the heat gained so we get

m_mc_m\Delta T_m=m_wc_w\Delta T_w\\\Rightarrow c_m=\dfrac{m_wc_w\Delta T_w}{m_m\Delta T_m}\\\Rightarrow c_m=\dfrac{150\times 4.186\times 2}{19\times 76}\\\Rightarrow c_m=0.8696\ \text{J/g}^{\circ}\text{C}

The specific heat of the metal is 0.8696\ \text{J/g}^{\circ}\text{C}.

4 0
3 years ago
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