Answer:
Step-by-step explanation:
Assuming the question wants you to write and equation passing through (2,-1); and parallel to y=-3/2x+6.
Then we use the slope intercept form:
We substitute the point and slope to get:
Note that parallel lines have the same gradient.
False,
So let's say that x is 2.
The statement is:
-2 + x is positive
-2 + 2 is positive
O is positive
This is not correct
Let's say that x is-2
-2 + x is positive
-2 + (-2) is positive
-2-2 is positive
-4 is positive
Answer:
Step-by-step explanation:
L = 2W + 5
A = LW = 63
L = 63/W
W=63/L
L = 2W + 5
63/W = 2W + 5
63 = 2WW + 5W
2WW + 5W - 63 = 0
2WW + 5W - 63 = 0
is already in quadratic equation form: ax^2 + bx + c = 0
use the quadratic formula to solve for two solutions:
x = ( -b +- sqrt( bb - 4ac ) ) / 2a
the two solutions are:
x = 9/2
x = -7
you cant have a negative solution for length so use the positive one
solve for length:
L=5+2(9/2)
L=5+18/2
L=5+9
L=14
Answer:
10
Step-by-step explanation:
f(4) if f(x) =3(x)-2
f(4)=3×4-2
= 12-2
= 10
i guess