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Oxana [17]
3 years ago
15

Tree pruning company A charges a one-time $100 equipment fee and charges $50 for each tree that it prunes. Tree pruning company

B charges a one-time $80 equipment fee and charges $60 for each tree that it prunes.
Let the variable t represent the number of trees pruned and let the variable c represent the cost. For how many pruned trees will the cost be the same for both companies?

Which system of equations can be used to solve this problem?

{c=50+100tc=60+80t

{c=150tc=140t

{c=100−50tc=80−60t

{c=100+50tc=80+60t
Mathematics
2 answers:
kobusy [5.1K]3 years ago
8 0
The total cost that a customer should incur in its dealings with company A should be, 
                              c = 50t + 100
For company B
                              c = 60t + 80
Equating these two charges
                               c = 50t + 100 = 60t + 80
Thus, the answer is the fourth choice. 
jek_recluse [69]3 years ago
4 0

the answer is

{c=100+50tc=80+60t

hope this helps

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Of the 480 flowers in a shop, 30% are lillies ,45% are orchids, and the rest are roses. How many roses are there in the shop?
Flura [38]
30 + 45 = 75

100 - 75 = 25

25% = 0.25

Multiply:

0.25 × 480 = 120

Answer = 120 roses

Hope this helped☺☺
4 0
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Whats the area help me youll get brainliest answer
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Answer:

<h2>Area = 14m²</h2>

<u>Step-by-step explanation:</u>

area of rectangle = length × breadth

area of rectangle = 4 × 2

area of rectangle = 8m²

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area of Triangle = 1/2 × 4 × 3

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Total area = 14m²

3 0
3 years ago
Solve each equation MUST SHOW WORK!!!! 10 points.
Sergio039 [100]

Answer:

1. x=34

2. c=8

3. x=9

4. m=32

That the answer for all 4.

Step-by-step explanation: Hope this help :D

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Which of the following functions gives the length of the base edge, aly, of a right square pyramid that is 8 inches tall as a fu
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How many different perfect cubes are among the positive actors of 2021^2021
9966 [12]

Answer:

hope this helps :D

Step-by-step explanation:

Perfect cube factors:

If a number is a perfect cube, then the power of the prime factors should be divisible by 3.

Example 1:Find the number of factors of293655118 that are perfect cube?

Solution: If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube 4x3x2x3=72

Perfect square and perfect cube

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.

Example 2: How many factors of 293655118 are both perfect square and perfect cube?

Solution: If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are 2x2x1x2=8

Example 3: How many factors of293655118are either perfect squares or perfect cubes but not both?

Solution:

Let A denotes set of numbers, which are perfect squares.

If a number is a perfect square, then the power of the prime factors should be divisible by 2. Hence perfect square factors must have

2(0 or 2 or 4 or 6 or 8)—– 5 factors

3(0 or 2 or 4 or 6)  —– 4 factors

5(0 or 2or 4 )——- 3 factors

11(0 or 2or 4 or6 or 8 )— 5 factors

Hence, the total number of factors which are perfect square i.e. n(A)=5x4x3x5=300

Let B denotes set of numbers, which are perfect cubes

If a number is a perfect cube, then the power of the prime factors should be divisible by 3. Hence perfect cube factors must have

2(0 or 3 or 6or 9)—– 4 factors

3(0 or 3 or 6)  —–  3  factors

5(0 or 3)——- 2 factors

11(0 or 3 or 6 )— 3 factors

Hence, the total number of factors which are perfect cube i.e. n(B)=4x3x2x3=72

If a number is both perfect square and perfect cube then the powers of prime factors must be divisible by 6.Hence both perfect square and perfect cube must have

2(0 or 6)—– 2 factors

3(0 or 6) —– 2 factors

5(0)——- 1 factor

11(0 or 6)— 2 factors

Hence total number of such factors are i.e.n(A∩B)=2x2x1x2=8

We are asked to calculate which are either perfect square or perfect cubes i.e.

n(A U B )= n(A) + n(B) – n(A∩B)

=300+72 – 8

=364

Hence required number of factors is 364.

8 0
3 years ago
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