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Amanda [17]
3 years ago
9

What is the interquartile range of this data set? A.6 B.8 C.9 D.20

Mathematics
1 answer:
ohaa [14]3 years ago
4 0
The interquartile range, IQR, is equal to the difference of Q1 and Q3 (first and third quartiles). These markers are visually shown as the edges of the box.

IQR = Q3 - Q1
IQR = 36 - 16
IQR = 20

Final Answer: Choice D) 20
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Answer:

(6,-6)

Step-by-step explanation:

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3 0
3 years ago
Read 2 more answers
PLEASE HELP me out with this
Black_prince [1.1K]
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6 0
2 years ago
Is 9/10 larger than 13/14
Reptile [31]

Answer:

13/14 is greater

Step-by-step explanation:

Find the lcm for both:

<u>9 x 7 </u>     = <u>63</u>

10 x 7        70

<u>13 x 5 </u>    = <u>65</u>

14 x 5        70

so therefore 13/14 is greater since it has a greater value when finding the lcm

5 0
3 years ago
at 6:00 a.m., the temperature is 58°. At 2:00 p.m., temperature is 76°. Find the rate of change in degrees per hour during this
lesya [120]

Answer:

The rate of change is of 2.25 degrees per hour.

Step-by-step explanation:

The rate of change in degrees per hour is given by by the change in temperature divided by the change in time(by number of hours).

In this question:

From 6 am to 2 pm, there are 12 - 6 + 2 - 0 = 6 + 2 = 8 hours

The change in temperature was of 76 - 58 = 18º

Rate of change:

18º/8 = 2.25º

The rate of change is of 2.25 degrees per hour.

6 0
2 years ago
In ΔABC, m∠A = 40°, m∠B = 60°. Find m∠C.
lana [24]
<span>m∠A = 40°
m∠B = 60°
m∠C = ?
There are 180 degrees in a triangle (not right) so you subtract both numbers by 180.
180degrees - 40 degrees - 60 degrees = 80 degrees</span>
4 0
3 years ago
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