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Furkat [3]
2 years ago
11

Given: 2x+30= -5(5x-2); Prove: x=-1

Mathematics
1 answer:
Viktor [21]2 years ago
5 0

Answer:

2(-1)+30=-5(5*-1-2)

-2+30=5(-5-2)

28 = 5(-7)

28= -35.

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Step-by-step explanation

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What is the image of (-6,-5) after a reflection over the -axis
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If the axis is x then you go to y so (6, 5)

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*PLEASE HELP WILL GIVE 60 POINTS I'M DESPERATE*
Zina [86]

Answer:

(0, 3)

Step-by-step explanation:

1. Find the slope:

\frac{y_{2} -y_{1} }{x_{2}-x_{1}  } =\frac{0-(-3)}{-4-(-8)}\\ \\=\frac{3}{4}

2. Calculate the y-intercept using a given point:

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3. Write in slope intercept form:

y= \frac{3}{4} x+3

Therefore, the y-intercept is 3.

The graph for this table is shown below.

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4 0
2 years ago
Read 2 more answers
How do i plug this in?
Temka [501]

Just jump the gun and multiply -7 and the value of d

-2[7x^2-24]-31

I got

-14x^2+17

as the total answer btw...

4 0
3 years ago
Please help, and thank you!
lawyer [7]

Answer:

3. C

4. D

Step-by-step explanation:

3.

x^2+25=0\\x^2=-25\\x=\pm\sqrt{-25}

Once \sqrt{-1}=i

x=\pm5i

4.

A quadratic equation has no real roots when the discriminant (\Delta) is negative. \Delta.

Let's try all the equations:

(A)

2x^2-7x-9=0\\\\\Delta=\sqrt{\left(-7\right)^2-4\cdot \:2\left(-9\right)}\\\Delta=\sqrt{\left(-7\right)^2+4\cdot \:2\cdot \:9}\\\Delta=\sqrt{121} \\\Delta=11

(B)

2x^2=7x\\2x^2-7x=0\\x(2x-7)=0\\x=0\\\text{or}\\2x-7=0\\2x=7\\\\

$x=\frac{7}{2} $

(C)

2x^2+7x-9=0\\\Delta = \sqrt{7^2-4\cdot \:2\left(-9\right)}\\\Delta = \sqrt{7^2+4\cdot \:2\cdot \:9}\\\Delta = \sqrt{121} \\\Delta= 11

(D)

2x^2-7x+9=0\\\Delta = \sqrt{\left(-7\right)^2-4\cdot \:2\cdot \:9}\\\\\Delta=\sqrt{-23} \\\Delta=\sqrt{23i}

8 0
3 years ago
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