First find the slope of the given line like this:

If two lines are parallel, then they have the same slope, so the equation we are looking for is in the form:

and we have to find b using the given point like this:
Substitute x = -2 and y=4 in the above equation like this and solve for a:
The equation of the line is then the following:
Answer:
A = 15 a²b²c² square units
Step-by-step explanation:
Area of a rectangle = LW
A = (1.5abc)(10abc)
A = 15 a²b²c² square units
The number of marbles in the bag illustrates probability
The conclusion about the number of marbles in the bag is that the bag can only contain one type of marble
<h3>The number of marbles in the bag?</h3>
The probabilities are given as:
P(Red) = 1
P(Green) = 1
For a distribution, the sum of all probabilities must equal to 1.
This means that:
P(Red) + P(Green) = 1
So, we have:
1 + 1 = 1
This gives
2 = 1
The above equation is false because 2 does not equal to 1.
So, the conclusion about the number of marbles in the bag is that the bag can only contain one type of marble i.e. either red marbles are in the bag or blue marbles are in the bag
Read more about probability at:
brainly.com/question/251701
Answer:
Both the boats will closet together at 2:21:36 pm.
Step-by-step explanation:
Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).
Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),
Formula : d=v*t
at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)
the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)
Formula : D=
⇒ 
Now let 
∵ 
⇒ t= 450/1250
⇒ t= .36 hours
⇒ = 21 min 36 sec
Since F"(t)=0,
∴ This time gives us a minimum.
Thus, The two boats will closet together at 2:21:36 pm.
Answer:
Yes
Step-by-step explanation:
To figure out if (1,2) is a solution to the system, we can plug the values in and see if it is true.
3x-2y=-1
3(1)-2(2)=-1
3-4=-1
-1=-1
It is true for this equation. Now let's check the next one.
y=-x+3
2=-(1)+3
2=2
Since both equations are true when we plug the values in, (1,2) is a solution to the system.