X = {3.898979486, -5.898979486}
x = {3.9 x -5.9}
The equation of the new function is ![g(x)= cos4 x+1](https://tex.z-dn.net/?f=g%28x%29%3D%20cos4%20x%2B1)
Explanation:
The Parent function is ![f(x)=cos x](https://tex.z-dn.net/?f=f%28x%29%3Dcos%20x)
We need to determine the new function g(x) using the transformation by stretching the f(x) horizontally by a factor of 4 and shifting it 1 unit up.
The function transformation formula is given by
![f(x)=a \cos b(x-c)+d](https://tex.z-dn.net/?f=f%28x%29%3Da%20%5Ccos%20b%28x-c%29%2Bd)
Where a stretches the function vertically
b compresses or stretches it horizontally,
c shifts the function left or right
d shifts the function up or down
Since, it is given that the function stretches horizontally by a factor of 4 and shifting it 1 unit up.
Hence,
and ![d=1](https://tex.z-dn.net/?f=d%3D1)
Substituting these values in the formula, we have,
![g(x)=cos4x+1](https://tex.z-dn.net/?f=g%28x%29%3Dcos4x%2B1)
Thus, the equation of the new function is ![g(x)= cos4 x+1](https://tex.z-dn.net/?f=g%28x%29%3D%20cos4%20x%2B1)
4.5*10^-1 =0.45
2*10^-2 = <span>=<span>150 </span></span><span>(Decimal: 0.02)</span>
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Answer: PQ=5, QR=radical 61= 7.81, angle: 50degrees,</span>Why:PQ=|-3|+2=5PR=6<span>angle Alfa, so there is right angle triangle PQR so I can use following formula:</span>PQ^2 + RP^2=QR^2;25 + 36=QR^2;QR=radical 61<span>also I can use: sinus (angle)=PR/QR;</span><span>sin(angle)=6/radical61=0.76822 which gives angle to be little bit more than 50 degrees{sinus 50 degrees=<span>0,7660</span>}. </span>