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3 years ago

10

Driving lessons are usually quite expensive but a discount of $15 per lesson is given if a member of the family is a member of t

he automobile club. If 10 lessons cost $760 (after the discount), find the cost of each lesson before the discount.

1 answer:

VLD [36.1K]3 years ago

7 0

The answer will be 0.66666666666

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Suppose that you were not given the sample mean and sample standard deviation and instead you were given a list of data for the

Troyanec [42]

Answer:

So, the sample mean is 31.3.

So, the sample standard deviation is 6.98.

Step-by-step explanation:

We have a list of data for the speeds (in miles per hour) of the 20 vehicles. So, N=20.

We calculate the sample mean :

$\mu=\frac{19 +19 +22 +24 +25 +27 +28+ 37 +35 +30+ 37+ 36+ 39+ 40+ 43+ 30+ 31+ 36+ 33+ 35}{20}\\\\\mu=\frac{626}{20}\\\\\mu=31.3$

So, the sample mean is 31.3.

We use the formula for a sample standard deviation:

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}$

Now, we calculate the sum

$\sum_{i=1}^{20}(x_i-31.3)^2=(19-31.3)^2+(19-31.3)^2+(22-31.3)^2+(24-31.3)^2+(25-31.3)^2+(27-31.3)^2+(28-31.3)^2+(37-31.3)^2+(35-31.3)^2+(30-31.3)^2+(37-31.3)^2+(36-31.3)^2+(39-31.3)^2+(40-31.3)^2+(43-31.3)^2+(30-31.3)^2+(31-31.3)^2+(36-31.3)^2+(33-31.3)^2+(35-31.3)^2\\\\\sum_{i=1}^{20}(x_i-31.3})^2=926.2\\$

Therefore, we get

$\sigma=\sqrt{\frac{1}{N-1}\sum_{i=1}^{N}(x_i-\mu)^2}\\\\\sigma=\sqrt{\frac{1}{19}\cdot926.2}\\\\\sigma=6.98$

So, the sample standard deviation is 6.98.

3 0

3 years ago

Help me please I’m not the smartest

viktelen [127]

X^2=16
x= 4 OR x=-4

The picture attached below is your answer because it’s between 4 and -4.

3 0

2 years ago

Round each decimal to the nearest whole number.<br><br> 6.85 <br> 0.37 <br> 2.5 <br> 16.1

Licemer1 [7]

Answer:

7

0.37 is closest to 0 but probably 1

3

16

5 0

2 years ago

I’ve been at these questions all day. Please help

Phantasy [73]

Answer:

தமிழ்நாட்டில் உள்ள நெல் வகைகளை குறிப்பிட்டு எழுதுக

7 0

3 years ago

Read 2 more answers

Dr black is standing 20 feet from street lamp lamp shadow is 5 feet long angle from top of his shadown to top of light is 30degr

s344n2d4d5 [400]

Then answer would be

90° < 0 < 180°.

hope it helps!

7 0

4 years ago