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2 years ago

Round to the nearest hundredth (2 decimal places) when necessary

Mathematics

1 answer:

shusha [124]2 years ago

8 0

Answer:

volume = 91 cm²

perimeter = 41.1 in

Step-by-step explanation:

volume = 1/2(b1+b2)(h) = 1/2(11 + 15)(7) = 91 cm²

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Aleonysh [2.5K]

Answer:

9. Force is required to change an object velocity.Force is equal to mass times acceleration.

10. Force acting on object are paired with equal and opposite forces

Step-by-step explanation:

Newton's 2nd law states that force is a product of mass and acceleration.In this case, the force of friction is causing deceleration of the ball.This is an example of rolling friction.Acceleration of the ball depends directly on this friction but indirectly on its mass.

10.

From Newton's 3rd Law ,for every action there is an equal and opposite reaction.The astronaut throwing the ball will experience the effect of an external force againts his own which is equal and in the opposite direction to the force she applied.This is why the astronaut moves backward but slower.

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3 years ago

Simplify the following expression: -8 (5b + 2) -7 ( b-5)

RUDIKE [14]

Answer:

-8(5b+2)-7(b-5)

first, use distributive property to get:

-40b-16-7b+35

then, use combine like terms to simplify:

-47b+19

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3 0

3 years ago

Read 2 more answers

What is the height of the cone below? - 3 - 9 - 27 - 75

Rasek [7]

$\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\ \end{cases}\implies V=\pi r^2\cdot \cfrac{h}{3}~~ \begin{cases} \pi r^2=&area~of\\ &circular\\ &base\\ \cline{1-2} \stackrel{B}{\pi r^2}=&5\\ V=&45 \end{cases} \\\\\\ 45=5\cdot \cfrac{h}{3}\implies 135=5h\implies \cfrac{135}{5}=h\implies 27=h$

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2 years ago

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the hardcover version of a book weighs 7 ounces while its paperback version weighs 5 ounces. Forty-five copies of the book weigh

Nuetrik [128]

Keywords:

System of equations, variables, hardcover version, paperback version, books

For this case we must construct a system of two equations with two variables. Let "h" be the number of hardcover version books, and let "p" be the number of paperback version books. If the hardcover version of a book weighs 7 ounces and the paperback version weighs 5 ounces, to reach a total of 249 ounces we have:

$7h + 5p = 249$ (1)

On the other hand, if there are Forty-five copies of the book then:

$h + p = 45$ (2)

If from (2) we clear the number of books paperback version we have:

$p = 45-h$

As each paperback version book weighs 5 ounces, to obtain the total weight of the paperback version books, represented by "x" in the table shown, we multiply $5 * p = 5 (45-h)$