Can you help me in my recent
Answer:
Either one of these.
Step-by-step explanation:
volumepile=1/3 (PI r^2)h
but r=h/2, so
volume=1/12 PI h^3
dv/dt=10 ft^3/min
but dv/dt=1/12 PI 3h^2 dh/dt
solve for dh/dt
This assumes you mean by "altitude" the height. If you mean altitude as slant height, you have to adjust the fromula
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given: r = h/2
V = (1/3)π r^2 h
= (1/3)π (h/2)^2 (h)
= (1/12) π h^3
dV/dt = (1/4)π h^2 dh/dt
for the given data ...
10 = (1/4)π(25)dh/dt
dh/dt = 10(4)/((25π) = 1.6/π feet/min
Answer: x = -2, y = -10
Step-by-step explanation:
solve for x first in the equation -2x+3=7
-2x+3=7
-2x = 4
x = -2
now plug that x value into the other equation so we can find y
3x+1 = 5+y
3(-2)+1 = 5+y
-6+1 = 5+y
-5=5+y
-10 = y
Answer:
I'd say A is the correct answer. There's a chance I'm wrong but I don't think so
