V = 1/3* h * r^3 pi
V ' = 1/3* h/3* (2r)^3 pi = h/9 * 8r^3 * pi
V ' / V = (h/9 * 8r^3 * pi) ÷ ( 1/3* h * r^3 pi ) = (8 * 3)/ 9 = 8 /3
R x 9
multiplication problem, r times 9
could also be 9r
So, the sphere went from 1.2 meters to 1.4 meters.
The radius will always be half of the diameter. So it went from .6 to .7.
Let's divide and see what percent .7 is of .6.
.7÷.6=1.166666666(repeating 6).
This means, it increased by about 16.7%, since it was not doubling, just going up.
Compare the two sets of numbers with a ratio. 1 can for 24 servings is to 1/2 can for x servings.
x= # servings from 1/2 can
1/24= (1/2)/x
cross multiply
1 * x= 24 * 1/2
x= 24/2
x= 12 servings
ANSWER: She can make 12 servings from 1/2 can of juice.
Hope this helps! :)
Answer:
The ship is located at (3,5)
Explanation:
In the first test, the equation of the position was:
5x² - y² = 20 ...........> equation I
In the second test, the equation of the position was:
y² - 2x² = 7 ..............> equation II
This equation can be rewritten as:
y² = 2x² + 7 ............> equation III
Since the ship did not move in the duration between the two tests, therefore, the position of the ship is the same in the two tests which means that:
equation I = equation II
To get the position of the ship, we will simply need to solve equation I and equation II simultaneously and get their solution.
Substitute with equation III in equation I to solve for x as follows:
5x²-y² = 20
5x² - (2x²+7) = 20
5x² - 2y² - 7 = 20
3x² = 27
x² = 9
x = <span>± </span>√9
We are given that the ship lies in the first quadrant. This means that both its x and y coordinates are positive. This means that:
x = √9 = 3
Substitute with x in equation III to get y as follows:
y² = 2x² + 7
y² = 2(3)² + 7
y = 18 + 7
y = 25
y = +√25
y = 5
Based on the above, the position of the ship is (3,5).
Hope this helps :)
