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MArishka [77]
4 years ago
9

Given the function f(x)= 3x^2 -15x + 18, evaluate f(-5)

Mathematics
1 answer:
givi [52]4 years ago
6 0
F=3/5x^2-3x+18/5 is the answers 
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olutions At the snack bar, hot dogs cost $4 each and bottled water costs $2 each. In the first business hour of the day, less th
ch4aika [34]

To solve the problem it is trial and error since we don’t know how many hotdogs and bottled water was sold. To trim down to problem, negative values and decimal values are not included because there is no negative amount and a decimal amount.

The equation is

4x + 2y > 12

At (0,6)

4(0) + 2(6) > 12

12 > 12 so it is wrong

At ( 2,1)

4(2) + 2(1) > 12

10 > 12 correct

At (1, 3)

4(1) + 2(3) > 12

10 > 12 correct

At (2,2)

4(2) + 2(2) > 12

12> 12 wrong


7 0
4 years ago
12 and 3000 as decimals full equation
ICE Princess25 [194]

Answer:

12=0.12x100

3000=0.3x10000

3 0
2 years ago
Do subtraction with monetory values.<br><br> $49.68 -$7.89=?
adell [148]

Answer:

U have $41.79 left i hope it is helpful have a nice day and merry Christmas

5 0
3 years ago
Read 2 more answers
When multiplying two negative numbers, what kind of number does one always get for an answer?
kvasek [131]

When we multiply two negative numbers, one always gets a positive number.

(-)×(-)= +

Hope it helps

4 0
3 years ago
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A keypad at the entrance of a building has 10 buttons labeled 0 through 9. What is the probability of a person correctly guessin
blondinia [14]

A keypad at the entrance of a building has 10 buttons labeled 0 through 9. What is the probability of a person correctly guessing a 9​-digit entry code if they know that no digits repeat?

Answer:

the probability of a person correctly guessing a 9​-digit entry code if they know that no digits repeat is 0.1

Step-by-step explanation:

We know that probability= number of required outcomes /number of all possible outcome.

From the given information;

the number of required outcome is guessing a 9-digit = 1  outcome

the number of all possible outcome = ¹⁰C₉ since there are 10 numbers and 9 number are to be selected.

Since there are only 9-digit that opens the lock;

the probability of a person correctly guessing a 9​-digit entry code is

P =\dfrac{1}{^{10}C_9}

P =\dfrac{1}{\dfrac{10!}{9!1!}}

P =\dfrac{1}{10}

P = 0.1

3 0
3 years ago
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