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Svetradugi [14.3K]
3 years ago
11

The table below is comparing level of education achieved to the rate of unemployment and the median weekly earnings in 2008. Bas

ed on the information provided, the unemployment rate decreases the most when moving between which two consecutive educational levels?
Two graphs connected by level of education are shown. First graph is titled Unemployment rate in 2008. Doctoral degree, 2; professional degree, 1.7; master's degree, 2.4; bachelor's degree, 2.8; associate degree, 3.7; some college, no degree, 5.1; high school graduate, 5.7; less than high school diploma, 9. Second graph is titled Median weekly earning in 2008. Doctoral degree, 1,555 dollars; professional degree, 1,522 dollars; master's degree, 1,228 dollars; bachelor's degree, 978 dollars; associate degree, 736 dollars; some college, no degree, 645 dollars; high school graduate, 591 dollars; less than a high school diploma, 426 dollars.
a.
“Less than high school” and “High School Graduate”

b.
“High school graduate” and “Some college, no degree”

c.
“Associate degree” and “Bachelor’s degree”

d.
“Professional degree” and “Doctoral degree”
Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
5 0

Answer:

A

Step-by-step explanation:

kicyunya [14]3 years ago
3 0

Answer:

Less than high school” and “ high school graduate”

Step-by-step explanation:

I know.

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8 0
3 years ago
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(3 points) Determine whether each of these functions f : {a, b, c, d} → {a, b, c, d} is one-to-one and whether each of these fun
finlep [7]

Answer:

Step-by-step explanation:

Recall the following. Given a function f we say that  

f is one to one if for x,y in the domain of f and f(x)=f(y) then x=y.

This means that there are no different elements in the domain of the function  that are linked to the same value.

f is onto if for every y in the codomain of f, then there is an element x in the domain of f such that f(x) = y. That is, given an element y in the codomain of f, there exists and element in the domain that is linked to y.

a)  

f(a) =b, f(b)=a, f(c) = c, f(d) = d. Note that this function links each element in {a,b,c,d} to different elements in {a,b,c,d}, so it is a one to one function. Since for every element x in {a,b,c,d} there is an element y in {a,b,c,d} such that f(y) = x, then this function is also onto.  

b)  

f(a)=b, f(b) = b, f(c) = d, f(d) = c. Note that the elements a,b are linked both to b, so this function fails to be one-to-one. Also, note that the element a has no element x in {a,b,c,d} such that f(x) = a, so this function fails to be onto.  

c)  

f(a) = d, f(b) = b, f(c) = c, f(d) = d.  

As in b), since a and d are linked to d, then this function is not one to one. Also, since the element a has no element x in {a,b,c,d} such that f(x) = a, then it also fails to be onto.  

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EleoNora [17]
The answer to this is A
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Answer:

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