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2 years ago

1. Find the sum of the measures of the interior angles of a regular 16-gon.

Mathematics

1 answer:

kenny6666 [7]2 years ago

5 0

Answer:

B. 2520 degrees.

Step-by-step explanation:

Sum of interior angles = 180(n - 2)

= 180(16-2)

= 2520 degrees.

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The clock below shows time that lance got home from school. 3:32. What time did he get home A: seventeen minutes before three B:

navik [9.2K]

Answer:

If Lance got home from school at 3:32 p.m. A and B both represent:

A: seventeen minutes before 3 would be before 3 o'clock even happens

B: 28 minutes before 4 would make more sense, since 3:32 is before 4 o'clock

Lance got home 28 minutes before 4

Hope this helps ;)

5 0

3 years ago

A random sample of 10 parking meters in a beach community showed the following incomes for a day. Assume the incomes are normall

Vlad1618 [11]

Answer: (2.54,6.86)

Step-by-step explanation:

Given : A random sample of 10 parking meters in a beach community showed the following incomes for a day.

We assume the incomes are normally distributed.

Mean income : $\mu=\dfrac{\sum^{10}_{i=1}x_i}{n}=\dfrac{47}{10}=4.7$

Standard deviation : $\sigma=\sqrt{\dfrac{\sum^{10}_{i=1}{(x_i-\mu)^2}}{n}}$

$=\sqrt{\dfrac{(1.1)^2+(0.2)^2+(1.9)^2+(1.6)^2+(2.1)^2+(0.5)^2+(2.05)^2+(0.45)^2+(3.3)^2+(1.7)^2}{10}}$

$=\dfrac{30.265}{10}=3.0265$

The confidence interval for the population mean (for sample size <30) is given by :-

$\mu\ \pm t_{n-1, \alpha/2}\times\dfrac{\sigma}{\sqrt{n}}$

Given significance level : $\alpha=1-0.95=0.05$

Critical value : $t_{n-1,\alpha/2}=t_{9,0.025}=2.262$

We assume that the population is normally distributed.

Now, the 95% confidence interval for the true mean will be :-

$4.7\ \pm\ 2.262\times\dfrac{3.0265}{\sqrt{10}} \\\\\approx4.7\pm2.16=(4.7-2.16\ ,\ 4.7+2.16)=(2.54,\ 6.86)$

Hence, 95% confidence interval for the true mean= (2.54,6.86)

7 0

3 years ago

Given the vectors, a=3i+4j, b=-2i+5j, c=10i-j, d=-1/3i+5/2j, find -0.4a-0.3b+0.2d=?

sveta [45]

Answer:

$-\frac{2}{3}i - \frac{13}{5}j$

Step-by-step explanation:

-0.4(3i + 4i) - 0.3(-2i + 5j) + 0.2(- $\frac{1}{3}i$ + $\frac{5}{2}$ j)

-1.2i - 1.6j + 0.6i - 1.5j - $\frac{0.2}{3}$ i + 0.5j

Converting to fraction form;

$-\frac{6}{5}i + \frac{3}{5}i - \frac{1}{15}i - \frac{8}{5}j - \frac{3}{2}j + \frac{1}{2} j$

<u>Solving the i part;</u>

$\frac{-18i + 9i - i}{15}$ = $-\frac{2}{3}i$

<u>Solving the j part;</u>

$\frac{-16j-15j+5j}{10} = -\frac{13}{5}$ j

So -0.4a - o.3b + 0.2d = $-\frac{2}{3}i$ - $\frac{13}{5}j$

6 0

3 years ago

Can someone pls help?

ratelena [41]

The measure of angle 8 is 88 degrees

6 0

3 years ago

Write the expression in complete n^2(n+8)-4(n+8)

MakcuM [25]

Answer:

(n^2-8)(n+8) is the answer

6 0

3 years ago