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3 years ago

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2 answers:

Sliva [168]3 years ago

6 0

Since there were three times as many student tickets sold, you can write the equation C = 3A C being children tickets and A being adult tickets

to get the total number of tickets sold you add children and adults so the equation would be C + A = 496

this is a substitution problem. where you take what C equals in the first equation, and plug it into C for the second equation

(3A) + A = 496
4A = 496
A = 124
so you now know that 124 adult tickets where sold.

Airida [17]3 years ago

3 0

A+s=496

s=496-a

and we are also told that:

s=3a

Since s=s we can say:

3a=496-a add a to both sides

4a=496 divide both sides by 4

a=124

So 124 adult tickets were sold.

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Find the measure of the missing angle *

lubasha [3.4K]

Answer:

21°

Step-by-step explanation:

we know that every single triangle has to equal 180°

we have all 3 angles 90° 34° 35° which equal 159°

so we take 180°-159° and your answer is 21°

6 0

3 years ago

Christi earns $21 per hour working as a receptionist. If she works 19 hours per week, what is her weekly wage? A) $250 B) $299 C

Vikentia [17]

Since Christi earns $21 per hour, to find how much she earns by working 19 hours per week we need to multiply the hourly wage by the number of hours she works in a week:

$21\times19=399$

Her weekly wage is $399

Answer: D) $399

7 0

1 year ago

9 to the power 18 = 27 to the power x work out the value of x

Strike441 [17]

Answer:

Step-by-step explanation:

27^x = 9÷(3^x)

So (3^3)^x = (3^2)÷(3^x)

So 3^3x = 3^(2-x)

Comparing powers on both sides,

3x = 2 - x

So, 4x = 2

So, x = 1/2

Given ( 27 ) ^ x = 9 / 3 ^x

⇒ ( 3 × 3 × 3 )^x = ( 3 × 3 ) / 3^x

⇒ ( 3 ³ )^x = 3² / 3^x

⇒ 3 ^ 3x × 3^x = 3² [ since ( a ^m)^n = a ^mn ]

⇒ 3^ (3x +x) = 3² [ since a^m × a^n = a ^m+n ]

⇒ 3^4x = 3²

⇒4x = 2 [ since If a ^m = a ^n then m = n ]

⇒ x = 2 / 4

∴ x = 1 / 2

I hope this helps you.

8 0

3 years ago

Find the zeros of y = x2 – 6x – 4 by completing the square.

katrin [286]

Answer:

The solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

Step-by-step explanation:

Given the function

$y\:=\:x^2\:-\:6x\:-\:4$

substitute y = 0 in the equation to determine the zeros

$0\:=\:x^2\:-\:6x\:-\:4$

Switch sides

$x^2-6x-4=0$

Add 4 to both sides

$x^2-6x-4+4=0+4$

Simplify

$x^2-6x=4$

Rewrite in the form (x+a)² = b

But, in order to rewrite in the form x²+2ax+a²

Solve for 'a'

2ax = -6x

a = -3

so add a² = (-3)² to both sides

$x^2-6x+\left(-3\right)^2=4+\left(-3\right)^2$

$x^2-6x+\left(-3\right)^2=13$

Apply perfect square formula: (a-b)² = a²-2ab+b²

$\left(x-3\right)^2=13$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solve

$x-3=\sqrt{13}$

Add 3 to both sides

$x-3+3=\sqrt{13}+3$

Simplify

$x=\sqrt{13}+3$

now solving

$x-3=-\sqrt{13}$

Add 3 to both sides

$x-3+3=-\sqrt{13}+3$

Simplify

$x=-\sqrt{13}+3$

Thus, the solutions to the quadratic equations are:

$x=\sqrt{13}+3,\:x=-\sqrt{13}+3$

4 0

3 years ago

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PolarNik [594]

Answer: 15 km/h

Step-by-step explanation:

8 0

3 years ago