A total of

2 answers:

6 0

Since there were three times as many student tickets sold, you can write the equation C = 3A C being children tickets and A being adult tickets

to get the total number of tickets sold you add children and adults so the equation would be C + A = 496

this is a substitution problem. where you take what C equals in the first equation, and plug it into C for the second equation

(3A) + A = 496
4A = 496
A = 124
so you now know that 124 adult tickets where sold.

Airida [17]2 years ago

3 0

A+s=496

s=496-a

and we are also told that:

s=3a

Since s=s we can say:

3a=496-a add a to both sides

4a=496 divide both sides by 4

a=124

So 124 adult tickets were sold.

You might be interested in

From 12,000 graphing calculators produced by a manufacturer, an inspector selects a random sample of 550 calculators and finds

maria [59]

Answer:

131

Step-by-step explanation:

Using proportion,

If Out of 550 calculators = 6 are defective,

Then out of 12000 calculators = ? are defective

$\frac{12000 calculators}{550calculators} * 6$

= 21.8 * 6

= 130.8 ≈ 131

∴ Approximately 131 calculators are defective

3 0

3 years ago

Planes Q and R are parallel. Lines a and b are shown on planes Q and R, respectively. Planes Q and R are parallel. Plane Q conta

natita [175]

Answer:

They are skew lines.

Step-by-step explanation:

Which statement is true about lines a and b?

They are parallel lines.

They are perpendicular lines.

They are skew lines.

They will intersect.

As they both are in different directions they are skew lines .

Skew lines are not parallel neither they .They are also not co planar i.e they lie in different planes.

We have two plane Q and R . We have two line a and b on the different planes Q and R. Both planes are parallel but the lines a and b are in different directions. Therefore they are skew lines . They do not intersect and are also not parallel neither co planar.