PLEASE HELP MEE I REALLY NEED HELP NOT TRYING TO BE ANNOYING BUT I NEED HELPP!!! Find the vertex of the graph of the quadratic f
1 answer:
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<h2>Explanation:</h2>
Hello, remember you need to write complete questions in order to get good and exact answers. Here you haven't provided any fractions, so I'll give you my own fractions.
The first fraction is:
The second fraction is:
So let's say that difference is:
Therefore, the result is:
The representation of this problem is shown using the number line below. As you can see, we have written both 1/2 and 1/4 and the difference is also indicated giving the result 1/4. That is, if we walk from 1/4 to 1/2 we'll walk 1/4 units.
Its not clearly given that whether EBF = 2x + 9 or 2x - 9.
I have written the solution for both.
If EBF = 2x + 9,
then ABF = 6x + 26 and ABE = 11x - 31.
Now, ABE = ABF + EBF
11x - 31 = (6x + 26) + (2x + 9)
= (6x + 2x) + (26 + 9)
= 8x + 35
11x - 8x = 35 + 31
3x = 66
x = 22
Therefore, ABF = 6x + 26 = 6(22) + 26 = 132 + 26 = 158°
If EBF = 2x - 9,
then ABF = 6x + 26 and ABE = 11x - 31.
Now, ABE = ABF + EBF
11x - 31 = (6x + 26) + (2x - 9)
= (6x + 2x) + (26 - 9)
= 8x + 17
11x - 8x = 17 + 31
3x = 48
x = 16
Therefore, ABF = 6x + 26 = 6(16) + 26 = 96 + 26 = 122°
