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forsale [732]
3 years ago
13

In a​ company, ​75% of the workers are women . If 1,475 people work for the company who​ aren't women ​, how many workers are th

ere in​ all? Use pencil and paper. Show two different ways that you can solve this problem.
Mathematics
1 answer:
Papessa [141]3 years ago
4 0

Answer:

re8gr7erhg89y8eh78erg87uhegrhurghu8grhugr

Step-by-step explanation:

rgefduwrguiurghiugrhigrhiugrhiughvuihriugfuiiugriugrhu

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Solve for x.* (4x + 7)° (6x + 3)° Sign​
Whitepunk [10]

24 x ^2 + 54 x + 21,

if you would like me to explain how to do it, I can in the comments.

3 0
4 years ago
The sales of a grocery store had an average of $8,000 per day. The store introduced several advertising campaigns in order to in
oksano4ka [1.4K]

Answer:

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

p_v =P(Z>2)=0.0228  

Step-by-step explanation:

1) Data given and notation  

\bar X=8300 represent the sample mean  

\sigma=1200 represent the population standard deviation  

n=64 sample size  

\mu_o =800 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

2) State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 8000, the system of hypothesis are :  

Null hypothesis:\mu \leq 8000  

Alternative hypothesis:\mu > 8000  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

3) Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{8300-8000}{\frac{1200}{\sqrt{64}}}=2  

4) P-value  

Since is a one-side upper test the p value would given by:  

p_v =P(Z>2)=0.0228  

5) Conclusion  

If we compare the p value and the significance level assumed, for example \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the mean is significantly higher than $8000.  

4 0
3 years ago
Jared and maila will usually both run 3 miles each time they go running .This month,jared ran an additional 21 miles. Which answ
jeyben [28]

Answer:

Total = m + j

= 3 + m + 21

Step-by-step explanation:

Mails = 3 miles

Jared = 3 miles + 21 miles

j = m + 21

m = 3

Total = m + j

= 3 + m + 21

Where,

m = 3

Total = 3 + m + 21

= 3 + 3 + 21

= 27

3 0
4 years ago
Find the value of each variable.<br> x = and y =
alex41 [277]

Answer:

x = 16

y = 16√3

Step-by-step explanation:

sin(30 degrees) = 1/2

x = 32/2 = 16

cos(30 degrees) = √3/2

y = 16√3

4 0
3 years ago
Read 2 more answers
What is the vertex of the parabola whose equation is y = (x + 1)2 + 3? (-1, -3) (-1, 3) (1, 3)
White raven [17]
Algebra:
A standard parabola is y = x^2. Its vertex is at (0,0)
You can change the position (or vertex) of the parabola.
To move a parabola across the x-axis, you can add or subtract a number from x WITHIN brackets of the ^2
eg. (x + 1)^2 will move the parabola across the x-axis. It will move is one unit to the LEFT (as the sign is opposite to the direction it moves ie. The sign it + but you move the whole parabola in the -ve direction).
Adding or subtracting a number from x OUTSIDE of the ^2 moves the parabola up or down the y-axis
eg. x^2 + 3 will move the parabola UP 3 units (the sign is the same as the direction it moves when the added/subtracted number is outside of the ^2 ie. the sign is positive so the parabola moves up in the positive direction)

From this, we can conclude that because (x + 1)^2 + 3, the vertex will be where x = -1 and where y = 3

Vertex : (-1,3)



Calculus:
f(x) = (x + 1)^2 + 3 = x^2 + 2x + 1 + 3 = x^2 + 2x + 4
Expanding the formular to make it easier to differentiate

f'(x) = 2x + 2
Differentiating (finding the formular the the gradiet of the parabola)

0 = 2x + 2
When the gradient is equal to zero, it must be the vertex

-2 = 2x
-2/2 = x
x = -1
Solve to give the x value at the vertex

f(x) = (x + 1)^2 + 3
= (-1 + 1)^2 + 3
Substitute x = -1 into original equatiom to find y value at the vertex

= (0)^2 + 3
= 0 + 3
= 3
Solve for y

Vertex : (-1,3)


6 0
3 years ago
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