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Eduardwww [97]
3 years ago
14

Match the expression on the left with its simplified form on the right. Answer options on the right may be used more than once.

Mathematics
2 answers:
Naily [24]3 years ago
5 0

Answer:

(-5) = -5

|-5| = 5

|5| = 5

-|5| = -5

-|-5| = -5

Aliun [14]3 years ago
3 0

Answer:

1. -5

2. 5

3. 5

4. -5

5. -5

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6 people shared 4 subs equally how much each get
telo118 [61]

Answer:

2/3

Step-by-step explanation:

4 subs 6 people

4/6= 0.66 repeated

so each person got 2/3 sub

3 0
3 years ago
If the sum of the zereos of the quadratic polynomial is 3x^2-(3k-2)x-(k-6) is equal to the product of the zereos, then find k?
lys-0071 [83]

Answer:

2

Step-by-step explanation:

So I'm going to use vieta's formula.

Let u and v the zeros of the given quadratic in ax^2+bx+c form.

By vieta's formula:

1) u+v=-b/a

2) uv=c/a

We are also given not by the formula but by this problem:

3) u+v=uv

If we plug 1) and 2) into 3) we get:

-b/a=c/a

Multiply both sides by a:

-b=c

Here we have:

a=3

b=-(3k-2)

c=-(k-6)

So we are solving

-b=c for k:

3k-2=-(k-6)

Distribute:

3k-2=-k+6

Add k on both sides:

4k-2=6

Add 2 on both side:

4k=8

Divide both sides by 4:

k=2

Let's check:

3x^2-(3k-2)x-(k-6) \text{ with }k=2:

3x^2-(3\cdot 2-2)x-(2-6)

3x^2-4x+4

I'm going to solve 3x^2-4x+4=0 for x using the quadratic formula:

\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\frac{4\pm \sqrt{(-4)^2-4(3)(4)}}{2(3)}

\frac{4\pm \sqrt{16-16(3)}}{6}

\frac{4\pm \sqrt{16}\sqrt{1-(3)}}{6}

\frac{4\pm 4\sqrt{-2}}{6}

\frac{2\pm 2\sqrt{-2}}{3}

\frac{2\pm 2i\sqrt{2}}{3}

Let's see if uv=u+v holds.

uv=\frac{2+2i\sqrt{2}}{3} \cdot \frac{2-2i\sqrt{2}}{3}

Keep in mind you are multiplying conjugates:

uv=\frac{1}{9}(4-4i^2(2))

uv=\frac{1}{9}(4+4(2))

uv=\frac{12}{9}=\frac{4}{3}

Let's see what u+v is now:

u+v=\frac{2+2i\sqrt{2}}{3}+\frac{2-2i\sqrt{2}}{3}

u+v=\frac{2}{3}+\frac{2}{3}=\frac{4}{3}

We have confirmed uv=u+v for k=2.

4 0
3 years ago
What is the answer beteen 8 and 10 when you divided by a fraction and a whole number
rewona [7]
The answer is 8and 10 when you divided is 0.8
5 0
3 years ago
In attempting to calculate the carrying capacity of a cylindrical pipe, Avery measured the outer diameter to be 2 inches, neglec
andreev551 [17]
Volume of the pipe = πr^2l
Wrong measure = π x (2)^2 x l = 4πl
Correct measure = π x (2 - 2(1/8))^2 x l = 49/16πl
error = 4πl - 49/16πl = 15/16πl

% error = ((15/16πl) / 49/16πl) x 100% = 30.6%
4 0
4 years ago
Answer the photo below thanks
MArishka [77]

Answer:

i think the answer is C

sorry if i am wrong

Step-by-step explanation:

7 0
3 years ago
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