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2 years ago

How does the electron-cloud model describe electrons?

Chemistry

1 answer:

Sav [38]2 years ago

7 0

Answer:

C. An electron has a high probability of being in certain regions.

Explanation:

In the electron cloud model, there are no electron-orbits around the nucleus but a cloud. This cloud has various densities with respect to distance from the nucleus. The most dense region of the cloud (which is the region close to the nucleus) is where electrons has the highest probability of existence.

The model explains that an electron a greater chance of being in the region closer to the nucleus. Thus, an electron has a high probability of being in certain region of the cloud about the central nucleus. And an electrostatic force exists between the nucleus and the electrons.

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Which of the following environmental risks is most likely to lead to digestive health issues?

algol13

Meat contamination because humans do not eat air or fertilizer so meat contamination is the only logical answer.

6 0

2 years ago

Read 2 more answers

Map<br> Formulate your hypothesis.<br> List down the materials.<br> • Write the methods.

Whitepunk [10]

Answer:

How to Formulate an Effective Research Hypothesis

State the problem that you are trying to solve. Make sure that the hypothesis clearly defines the topic and the focus of the experiment.

Try to write the hypothesis as an if-then statement. ...

Define the variables.

Explanation:

5 0

2 years ago

Burka [1]

Answer:

$\large \boxed{\text{E) 721 K; B) 86.7 g}}$

Explanation:

Question 7.

We can use the Combined Gas Laws to solve this question.

a) Data

p₁ = 1.88 atm; p₂ = 2.50 atm

V₁ = 285 mL; V₂ = 435 mL

T₁ = 355 K; T₂ = ?

b) Calculation

$\begin{array}{rcl}\dfrac{p_{1}V_{1}}{T_{1}}& =&\dfrac{p_{2}V_{2}}{T_{2}}\\\\\dfrac{1.88\times285}{355} &= &\dfrac{2.50\times 435}{T_{2}}\\\\1.509& = &\dfrac{1088}{T_{2}}\\\\1.509T_{2} & = & 1088\\T_{2} & = & \dfrac{1088}{1.509}\\\\ & = & \textbf{721K}\\\end{array}\\\text{The gas must be heated to $\large \boxed{\textbf{721 K}}$}$

Question 8. I

We can use the Ideal Gas Law to solve this question.

pV = nRT

n = m/M

pV = (m/M)RT = mRT/M

a) Data:

p = 4.58 atm

V = 13.0 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 385 K

M = 46.01 g/mol

(b) Calculation

$\begin{array}{rcl}pV & = & \dfrac{mRT}{M}\\\\4.58 \times 13.0 & = & \dfrac{m\times 0.08206\times 385}{46.01}\\\\59.54 & = & 0.6867m\\m & = & \dfrac{59.54}{0.6867 }\\\\ & = & \textbf{86.7 g}\\\end{array}\\\text{The mass of NO$_{2}$ is $\large \boxed{\textbf{86.7 g}}$}$

7 0

2 years ago

How many grams of H2O2 are in 3 moles of H2O2?

stira [4]

Answer:

The answer is 102.3!

Explanation:

you get this by multiplying 34.1 x 3 to get 102.3.

Wondering why you multiply 34.1 times 3?

WELLLLLLLLLLL...

when you get 1 mole of h202, you get 34.1 so if you ask for 3 moles of H202, you get 102.3!

4 0

1 year ago

Calculate the volume of the gas, in liters, if 1.35 mol

Alina [70]

Answer:

22.8 L

Explanation:

Step 1: Given data

Moles of the gas (n): 1.35 mol

Pressure of the gas (P): 1.30 atm

Temperature (T): -6°C

Ideal gas constant (R): 0.0821 atm.L/mol.K

Step 2: Convert "T" to Kelvin

We will use the following expression.

K = °C + 273.15 = -6 + 273.15 = 267 K

Step 3: Calculate the volume of the gas

We will use the ideal gas equation.

P × V = n × R × T

V = n × R × T / P

V = 1.35 mol × (0.0821 atm.L/mol.K) × 267 K / 1.30 atm

V = 22.8 L

7 0

3 years ago