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avanturin [10]
3 years ago
11

What is the mass, in grams of a pure iron cube that has a volume of 4.20cm^3

Chemistry
1 answer:
Dmitriy789 [7]3 years ago
6 0
d_{Fe}=7874\frac{kg}{m^{3}}=7,874\frac{g}{cm^{3}}\\
V=4,2cm^{3}\\\\
m=dV=7,784\frac{g}{cm^{3}}*4,2cm^{3}\approx 32,7g
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