3 years ago

What is the mass, in grams of a pure iron cube that has a volume of 4.20cm^3

Chemistry

1 answer:

Dmitriy789 [7]3 years ago

6 0

$d_{Fe}=7874\frac{kg}{m^{3}}=7,874\frac{g}{cm^{3}}\\
V=4,2cm^{3}\\\\
m=dV=7,784\frac{g}{cm^{3}}*4,2cm^{3}\approx 32,7g$

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