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Aleks04 [339]
3 years ago
7

1 point

Physics
1 answer:
marta [7]3 years ago
7 0

Answer:

Let, R be the resistance of the heater wire. Since, two heater wires are of equal length their resistance is also same.

Hence, for series combination of resistances,

R

s

=2R

And for parallel combination of resistances,

R

p

=

2

R

Now, heat produced when they first connected in series is

H

s

=

R

s

V

2

where, V is voltage supplied to the heater.

H

s

=

2R

V

2

.....................................(1)

heat produced when they first connected in series is

H

p

=

R

p

V

2

H

p

=

2

R

V

2

H

p

=

R

2V

2

............................................(2)

From (1) and (2), we get

H

p

H

s

=

R

2V

2

2R

V

2

⇒

H

p

H

s

=

4

1

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A Porsche challenges a Honda to a 200-m race.Because the Porsche's acceleration of 3.5 m/s2 is larger than the Honda's 3.0 m/s2,
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Answer:

Honda won by 0.14 s

Explanation:

We are given that

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Time taken by Honda  to start=1 s

s=ut+\frac{1}{2}at^2

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200=0(t)+\frac{1}{2}(3)t^2

200=\frac{3}{2}t^2

t^2=\frac{200\times 2}{3}=\frac{400}{3}

t=\sqrt{\frac{400}{3}}=11.55s

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200=\frac{1}{2}(3.5)t^2

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3 0
3 years ago
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vlada-n [284]

Answer:

idk

Explanation:

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Sergio039 [100]

Answer:

The correct answer is B

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