Answer:
u" + 40u' + 49u = 2 sin(t/6)
upp + 40up + 49u = 2 sin(t/6)
Explanation:
Step 1: Data given
mass = 5 kg
L = 20 cm = 0.2 m
F = 10 sin(t/6)N
Fd(t) = - 6 N
u(0) = 0.03 m/s
u(0) = 0
u'(0) = 3 cm/s
Step 2:
ω =kL
k = ω/L = m*g /L = (5*9.8)/0.2 = 245 kg/s²
Since Fd(t) = -γu'(t) we know:
γ =- Fd(t) / u'(t) = 6N/ 0.03 m/s = 200 Ns/m
The initial value problem which describes the motion of the mass is given by
5u" + 200u' + 245u = 10 sin(t/6) u(0) = 0 ; u'(0) = 0.03
This is equivalent to:
u" + 40u' + 49u = 2 sin(t/6) u(0) = 0 ; u'(0) = 0.03
upp + 40up + 49u = 2 sin(t/6)
With u in m and t in s
__Protons and neutrons have similar mass.
__Electrons are smaller than a proton or a neutron.
Explanation:
The three particles involved in this problem are:
- Proton: it is positively charge, it is found in the nucleus of the atom, and its mass is

- Neutron: it has no electric charge, it is also found in the nucleus of the atom, and its mass is approximately equal to that of the proton (just slightly larger)
- Electron: it has negative electric charge, it orbit around the nucleus of the atom, and its mass is much smaller than that of the proton:

We can now analyze each of the given statement:
__Protons and neutrons have similar mass. --> TRUE
__Protons and electrons have similar mass. --> FALSE, the electron is much lighter
__Neutrons and electrons have similar mass. --> FALSE, the neutron is much heavier
__Protons are smaller than a neutron or an electron. --> FALSE, protons are similar to the neutrons
__Neutrons are smaller than a proton or an electron. --> FALSE, neutrons are similar to the protons
__Electrons are smaller than a proton or a neutron. --> TRUE
Learn more about atoms:
brainly.com/question/2757829
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Explanation:
It is given that,
Speed of the ball, v = 10 m/s
Initial position of ball above ground, h = 20 m
(a) Let H is the maximum height reached by the ball. It can be calculated using the conservation of energy as :


h' = 5.1 m
The maximum height above ground,
H = 5.1 + 20
H = 25.1 meters
So, the maximum height reached by the ball is 25.1 meters.
(b) The ball's speed as it passes the window on its way down is same as the initial speed i.e. 10 m/s.
Hence, this is the required solution.
><span>It can travel through vacuum.
The rays must travel in the vacuum of space between Earth's atmosphere and the sun.</span>
Answer:
Both A and C
Explanation:
I just got it correct on Edg