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Temka [501]
3 years ago
5

What is described by the terms body-centered cubic and face-centered cubic?

Physics
1 answer:
Montano1993 [528]3 years ago
7 0
In physical chemistry, the terms body-centered cubic  (BCC) and face-centered cubic (FCC) refer to the cubic crystal system of a solid. Each solid is made up simple building blocks called lattice units. There are different layouts of a lattice unit.

It is better understood using 3-D models shown in the picture. A BCC unit cell has one lattice point in the center, together with eight corner atoms which represents 1/8 of an atom. Therefore, there are 1+ 8(1/8) = 2 atoms in a BCC unit cell. On the other hand, a FCC unit cell is composed of half of an atom in each of its faces and 1/8 of an atom in its corners. Therefore, there are (1/2)6 + (1/8)8 = 4 atoms in a FCC unit cell.

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3 years ago
A sinusoidal wave traveling on a string has a period of 0.20 s, a wavelength of 32 cm, and an amplitude of 3 cm. The speed of th
Finger [1]

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v = 1.6 \frac{m}{s} *\frac{100cm}{1m}= 160 \frac{cm}{s}

Explanation:

If we have a periodic wave we need to satisfy the following basic relationship:

v = \lambda f

From the last formula we see that the velocity is proportional fo the frequency.

For this case we have the following info given by the problem:

T= 0.2 s, \lambda =32 cm* \frac{1m}{100cm} =0.32 m, A= 3cm*\frac{1m}{100 cm}=0.03 m

We know that the frequency is the reciprocal of the period so we have this formula:

f = \frac{1}{T}

And if we replace we got:

f =\frac{1}{0.2 s}= 5Hz

Now since we have the value for the wavelength we can find the velocity like this:

v = 0.32 m * 5Hz = 1.6 \frac{m}{s}

And if we convert this into cm/s we got:

v = 1.6 \frac{m}{s} *\frac{100cm}{1m}= 160 \frac{cm}{s}

6 0
3 years ago
What is the acceleration during the pushing-off phase, in m/27 Express your answer in meters per second squared. A bush baby, an
Sindrei [870]

Answer:

a = 12.78 g's

Explanation:

Height reached by the object after push off is given as

H = 2.3 m

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now we have

0 - v^2 = 2(-9.81)(2.3)

v = 6.72 m/s

now we know that this push last for total distance of 0.18 m

so during the push we will have

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a = 12.78 g's

6 0
3 years ago
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