Yeah, I think that's the correct graph.
The fraction of a defective item getting by both inspectors is
= 
Step-by-step explanation:
Step 1; Assume that the probability of the first inspector missing a defective part is P(A) and the probability of the second inspector missing those that do get past the first inspector is P(B).
Step 2; It is given that P(A) = 0.1, we convert this into a fraction so that the final probability will be a fraction and not a decimal.
P(A) = 0.1 =
.
It is given that the second inspector misses 5 out of 10 that get past the first inspector, so P(B) =
.
Step 3; To calculate the probability of both inspectors missing a defective part, we multiply both the probabilities.
P(A and B happening) = P(A) × P(B) =
×
=
=
= 0.05%. So there is a 0.05% chance of both inspectors missing a defective part.
Answer:
The value of X is more than equal to -1.83.
Step-by-step explanation:
We need to find the correct representation of the inequality 'minus 32X -5 less than 52 minus X'
LHS of the inequality will be : -32x-5
RHS of the inequality will be : (52-X)
So,

Adding X both sides

Adding 5 to both sides,

Dividing both sides by -31.

So, the value of X is more than equal to -1.83.
Holy god gud luck on escaping that (*´ー`*)
<span>Just do 11-2 to get 9 so your answer is x to the 9th power where 9 is the exponent. Remember if u have to divide two numbers (same base or same number) and they have different exponents just subtract the exponents (top exponent minus bottom exponent)</span>