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Katarina [22]
3 years ago
13

tamara find the sum of two number cubes rolled at the same time. The chart below shows all possible sums from the 36 possible co

mbinations when rolling two number cubes. How many times should tamara expect the sum of the two cubes be equal to 5 if she rolls the two number cubes 144 times?
Mathematics
1 answer:
Reil [10]3 years ago
6 0

Answer:

the answer would be 20 :)

Step-by-step explanation:

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Five numbers have a range of 14. Four of the numbers are 20, 22, 31 and 25. Work out the two different possible values for the f
Pepsi [2]

Answer:

17

34

Step-by-step explanation:

Range is the difference between the highest and lowest values of a set of observations

Range = highest value - lowest value

the missing number can either by the highest value or the lowest value. this is because none of the numbers given when subtracted from each other would give a value of 14

let x = missing number

14 = x - 20

x = 20 + 14 = 34

or

14 = 31 - x

x = 31 - 14

x = 17

6 0
3 years ago
Evaluate using integration by parts ​
PolarNik [594]

Rather than carrying out IBP several times, let's establish a more general result. Let

I(n)=\displaystyle\int x^ne^x\,\mathrm dx

One round of IBP, setting

u=x^n\implies\mathrm du=nx^{n-1}\,\mathrm dx

\mathrm dv=e^x\,\mathrm dx\implies v=e^x

gives

\displaystyle I(n)=x^ne^x-n\int x^{n-1}e^x\,\mathrm dx

I(n)=x^ne^x-nI(n-1)

This is called a power-reduction formula. We could try solving for I(n) explicitly, but no need. n=5 is small enough to just expand I(5) as much as we need to.

I(5)=x^5e^x-5I(4)

I(5)=x^5e^x-5(x^4e^x-4I(3))=(x-5)x^4e^x+20I(3)

I(5)=(x-5)x^4e^x+20(x^3e^x-3I(2))=(x^2-5x+20)x^3e^x-60I(2)

I(5)=(x^2-5x+20)x^3e^x-60(x^2e^x-2I(1))=(x^3-5x^2+20x-60)x^2e^x+120I(1)

I(5)=(x^3-5x^2+20x-60)x^2e^x+120(xe^x-I(0))

Finally,

I(0)=\displaystyle\int e^x\,\mathrm dx=e^x+C

so we end up with

I(5)=(x^4-5x^3+20x^2-60x+120)xe^x-120e^x+C

I(5)=(x^5-5x^4+20x^3-60x^2+120x-120)e^x+C

and the antiderivative is

\displaystyle\int2x^5e^x\,\mathrm dx=(2x^5-10x^4+40x^3-120x^2+240x-240)e^x+C

8 0
3 years ago
Need a little help with one please
Pani-rosa [81]

Answer:

That would be the side-side-side (SSS) postulate, which states that if all the sides of a triangle are in a fixed ratio to all the corresponding sides of another triangle, then the two triangles are said to be congruent.

Step-by-step explanation:

Looking at triangles ABC and DEF, we notice that:

\frac{AB}{DE} = \frac{AC}{DF}=\frac{BC}{EF}

since

\frac{3}{18} = \frac{6}{36}=\frac{7}{42}=\frac{1}{6}

Let me know if you have further questions.

4 0
3 years ago
Two cones have a radius of 2 cm. The height of one cone is 8 cm. The other cone is 1/4 of that height. Which of these statements
marta [7]
The wrong statement: The volume or the smaller cone cannot be determined because its height is unknown.

We already know that the larger cone has a height of 8 cm and that the smaller cone is just 1/4 of 8 cm.

8×1/4 = 2 cm.

You can still find its volume by using the formula 1/3πr^2.
8 0
3 years ago
Read 2 more answers
Solve 8 = 2^x + 4<br> x = −4<br><br> x = −1<br><br> x = 0<br><br> x = 7
TEA [102]
None of these answers match up to the equation. The answer is 2. 2^2, 2x2=4
4+4=8
8=2^2+4
8 0
3 years ago
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