All categories

3 years ago

Asappppppppppp plzzzzzz

Mathematics

1 answer:

blondinia [14]3 years ago

3 0

7289hdkshi h was gd J s hi bus my ejj on Sindhi b B t bcudii I did

You might be interested in

In the 2014 - 2015 school year, the mean score on the critical reading of the SAT was 490 with a standard deviation of 102 for j

bonufazy [111]

<u>Answer:</u>

The Ranking Percentile is (B) 97.5%

<u>Explanation :</u>

To find the percentile rank we need to find the z- score. After finding the z-score match this value with the corresponding value in z-score table.

Formula to find the z-score

Z-score= $\frac{\text { scored obtained - mean }(\mu)}{\text { standard deviation }(\sigma)}$

Substituting the values in the above equation, we find

Z-score= $\frac{(694-490)}{102}$ =2

So, the Z-score is +2

Now, the corresponding value of Z-score 2 in the table is 0.9772

or the percentile score is 97.72 ~ 97.5 .

3 0

3 years ago

Sorry to bother you, but I am STUGGLYINGGG

Y_Kistochka [10]

I think the answer is a

6 0

2 years ago

Read 2 more answers

Find the angle between the vectors u=i-9j and v=8i+5j

Katyanochek1 [597]

Answer: $\cos^{-1} \left(\frac{-37}{\sqrt{7298}} \right) \approx 115.665^{\circ}$

Step-by-step explanation:

$u \cdot v=(1)(8)+(-9)(5)=-37\\\\|u|=\sqrt{1^{2}+(-9)^{2}}=\sqrt{82}\\\\|v|=\sqrt{8^{2}+5^{2}}=\sqrt{89}\\\\\cos \theta=\frac{-37}{\sqrt{82}\sqrt{89}}\\\\\theta=\cos^{-1} \left(\frac{-37}{\sqrt{82}\sqrt{89}} \right)\\\\\theta=\boxed{\cos^{-1} \left(\frac{-37}{\sqrt{7298}} \right) \approx 115.665^{\circ}}$

7 0

2 years ago

What is 15% of 60? Create a model to prove your answer (this is the question. I didn't really understand today's lesson in class

skelet666 [1.2K]

If you have instagram dm me and ill show you how to make the graph my instagram is ____ella.grace____ 4 underscores btw

8 0

3 years ago

Find the difference using suitable identity (10.3 × 9.7) – (10.7 × 9.3)

finlep [7]

Answer:

$\small\textrm\red{-------------------------------------------------------------------}$ $\small\textrm\blue{-------------------------------------------------------------------}$ $\small\textrm\green{-------------------------------------------------------------------}$ $\small\textrm\blue{-------------------------------------------------------------------}$ mag sayaw ka nalang

$\small\textrm\green{-------------------------------------------------------------------}$ $\small\textrm\blue{-------------------------------------------------------------------}$ $\small\textrm\blue{-------------------------------------------------------------------}$ $\small\textrm\red{-------------------------------------------------------------------}$

5 0

3 years ago