Answer:
Standard Deviation = 3.22
Variance = 10.36
Step-by-step explanation:
x P(x) x × P(x) x² x² × P(x)
19 0.20 3.8 361 72.2
10 0.20 2 100 20
11 0.30 3.3 121 36.3
12 0.20 2.4 144 28.8
13 0.10 1.3 169 16.9
____________________________________________
12.8 174.2 => Total
<em><u>Mean Formula</u></em>
<em><u>Variance Formula</u></em>
![\sigma _x^2 = \sum[x^2 \times P(x)] - \mu_x^2](https://tex.z-dn.net/?f=%5Csigma%20_x%5E2%20%3D%20%5Csum%5Bx%5E2%20%5Ctimes%20P%28x%29%5D%20-%20%5Cmu_x%5E2)
<em><u>Standard Deviation Formula</u></em>
17/29 + 6/29 + 4/29
= 27/30
<span>1 - 27/29 = 2/29 = 0.069</span>
Okay, so here is a small lesson on rounding. When you round you MUST know the place value of each number. Ones, tens, hundreds, thousands, millions.
So, when we look at this number what do we have in the ones place --there is a 0 -- in the tens place we have a 9 and in the the thousands place we have 5. to round this number look at the tens place. if the number is greater than 5 you round 73590 to 73600, if it is 4 and lower it stays the same and the numbers behind change to zero--> like so 73500. But for this problem it would round up to 73600.
Answer:
5 milk shakes
Step-by-step explanation:
From the above question, we know that for the recipe
1/3 cup of milk = 1 milk shake
15/8 cup of milk = y milk shakes
We cross Multiply
15/8 cup × 1 = 1/3cup × y
y = 15/8 cup × 1 /1/3cup
= 15/8 ÷ 1/3
= 15/8 × 3
= 45/8
= 5.625 of 5 5/8 cups of milk
Therefore, the maximum number of
milkshakes the server can make following the recipe porpotians is 5 milk shakes.
Answer:
multiply
Step-by-step explanation:
just multiply all of them and then u will get your answer I hope this helped ❤
