It is obvious that Triangle BCD is congruent to Triangle EFG. EFG is twice the size of BCD.
Put the lengths into the pythagorean theorem equation. (the longest side is the hypotenuse)
So for Triangle BCD
3^2+b^2=5^2
(3×3)+b^2=(5×5)
9+b^2=25
So what plus 9 equals 25?
16
the square root of 16 is 4 so 4^2=16
9+16=25
Now since we know that Triangle EFG is twice the size of BCD remake the equation but the numbers will be:
6^2+8^2=10^2
Now check
(6×6)+(8×8)=(10×10)
36+64=100
100=100
So for Triangle EFG X=8
Standard form is x + y = number
y + 4 = -6(x + 6)
y + 4 = -6x + -36
y = -6x - 40
6x + y = -40
<span>2x(x - 3)(x + 2)
= </span><span>2x(x^2 - 3x + 2x - 6)
</span>= 2x(x^2 - x - 6)
= 2x^3 - 2x^2 - 12x
Answer:
The length of the ramp is x = AC = 10.35 feet
Step-by-step explanation:
From the ΔABC
AC = x = length of ramp
BC = 10 feet
°
x = 10.35 feet
Therefore the length of the ramp is x = AC = 10.35 feet
Answer:
D
Step-by-step explanation: