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svet-max [94.6K]
3 years ago
10

Someone please help me answer this!!!

Mathematics
2 answers:
makkiz [27]3 years ago
8 0

Answer:

n = 9

Step-by-step explanation:

hey mate make my answer brainiest

(x*3)*3=x*n

3×3=n. (reason when bases are same powers are also same)

9=n

n=9

I hope this helps

Norma-Jean [14]3 years ago
4 0

Answer:

n = 9

Step-by-step explanation:

Using index laws, multiply 3 into 3 to get 9

(x3)^3 = x^n

x^9 = x^n

9 = n

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X+78=3x-2 <br> ..................
photoshop1234 [79]

Answer:

x=40

Step-by-step explanation:

x+78=3x-2\\\mathrm{Subtract\:}78\mathrm{\:from\:both\:sides}\\x+78-78=3x-2-78\\x=3x-80\\\mathrm{Subtract\:}3x\mathrm{\:from\:both\:sides}\\x-3x=3x-80-3x\\\\

-2x=-80\\\frac{-2x}{-2}=\frac{-80}{-2}\\x=40

6 0
3 years ago
What’s the product of 0.54(8)
maw [93]

The answer to your problem is 4.32.

6 0
3 years ago
What percent of 15% of 60
AveGali [126]

Answer:

the answer is 9

Step-by-step explanation:

15/100 ?/60

multiply 60 by 15 to get 900, the divide 900 by 100 to get <em>9</em>

4 0
3 years ago
Please solve this question <br>the answer is 45 degree ​
malfutka [58]

Answer:

∠ABC= 45°

Step-by-step explanation:

∠ABC= ∠BCD (alt. ∠s, AB//CD)

(2x +15)°= (3x)°

2x +15= 3x

3x-2x= 15 <em>(</em><em>-2x </em><em>on </em><em>both </em><em>sides)</em>

x= 15

Substituting the value of x:

∠ABC

= ∠BCD

= [3(15)]°

= 45°

7 0
3 years ago
F divides HJ in the ratio 3:1. If H = (-11,7) and J = (5,3), what are the<br> coordinates of F?
Hatshy [7]

Answer:

The coordinates of HF are (1, 4)

Step-by-step explanation:

The parameters of the line are;

The coordinate of the end points are H = (-11, 7), and J = (5, 3)

The ratio by which the point F divides the line = 3:1

The segments in the line are HF, and FJ

Therefore;

The fraction of the length of HJ that is represented by HF = 3/(3 + 1) × HJ = 3/4 × HJ

HF = 3/4 × HJ

Which gives the coordinates of the point F as follows;

Coordinate of F = (-11 +(5 - (-11))×3/4, 7 + (3 - 7)×3/4) =  (1, 4)

The coordinates of F are (1, 4)

We check the length of HF, from the equation for the length to of a line to get;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

l_{HF} = \sqrt{\left (4-7  \right )^{2}+\left (1-(-11)  \right )^{2}} = \sqrt{\left (-3  \right )^{2}+\left (12  \right )^{2}} = 3\cdot \sqrt{17}

Similarly, we check the length of HJ, to get;

l_{HF} = \sqrt{\left (3-7  \right )^{2}+\left (5-(-11)  \right )^{2}} = \sqrt{\left (-4  \right )^{2}+\left (16  \right )^{2}} = 4\cdot \sqrt{17}

The length of HF = 3·√(17)

The length of HJ = 4·√(17)

Therefore, from HF = 3/4× HJ, we have;

HF = 3/4 × 4·√(17) = 3·√(17)

Therefore, the coordinates of HF are (1, 4)

7 0
3 years ago
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