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Nostrana [21]
3 years ago
9

Find the zeros of the function !! g(x)=(x-2)(3x+3) lesser x= ? greater x= ?

Mathematics
1 answer:
marin [14]3 years ago
3 0

Answer:

Step-by-step explanation:

Rewrite this function as g(x) = 3(x + 1)(x - 2)

Set each factor equal to zero in turn, solving for x each time:

x + 1 => x = -1  (the lesser zero)

x - 2  =>  x = 2  (the greater zero)

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Y=-x - 3<br> What so the value of x
Sergeu [11.5K]

Answer:

x=−y−3

Step-by-step explanation:

Step 1: Flip the equation.

−x−3=y

Step 2: Add 3 to both sides.

−x−3+3=y+3

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Step 3: Divide both sides by -1.

\frac{-x}{-1} = \frac{y+3}{-1}

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6 0
3 years ago
Which is the best estimate for 6.3×10 to the second power times 9.9×10 to the 3rd power written in scientific notation
viva [34]

Answer:

in scientific notation, the expression can be written as 6.237 x 10⁶

Step-by-step explanation:

Given;

6.3×10 to the second power times 9.9×10 to the 3rd power

Using scientific notation, it can be interpreted as;

(6.3 \times 10^2) \times (9.9 \times 10^3)

This can be simplified as;

(6.3 \times 10^2) \times (9.9 \times 10^3) = (6.3\times 9.9)\times 10^{2+3}\\\\= 62.37\times 10^5 = 6.237\times 10^6

Therefore, in scientific notation, the expression can be written as 6.237 x 10⁶

4 0
3 years ago
Evaluate (-5)^2<br> 10<br> -10<br> 25<br> -25
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Find the lengths of the sides of the triangle PQR. Is it a right triangle? Is it an isoseceles triangle?(a)P(3,−2,−3),Q(7,0,1),R
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Answer:

(a) It is an isosceles triangle with sides of lengths: 6, 2√10, and 6 units.

(b) It is a right-angled triangle with hypotenuse side of 3√5 units, and opposite and adjacent sides of 6 and 3 units

Step-by-step explanation:

(a) P(3,−2,−3), Q(7,0,1), R(1,2,1)

|PQ| = √[(7-3)² + (0+2)² + (1+3)²]

= √(4² + 2² + 4²)

= √36

= 6

|QR| = √[(1-7)² + (2-0)² + (1-1)²]

= √((-6)² + 2² + 0)

= √40

= 2√10

|RP| = √[(3-1)² (-2-2)² (-3-1)²]

= √[(2² + (-4)² + (-4)²]

= √36

= 6

|PQ| = |RP|

So, triangle is isosceles.

(b) P(2,−1,0), Q(4,1,1), R(4,−5,4)

|PQ| = √[(4-2)² + (1+1)² + (1-0)²]

= √(2² + 2² + 1²)

= √9

= 3

|QR| = √[(4-4)² (-5-1)² (4-1)²]

= √[(0 + (-6)² + 3²]

= √45

= 3√5

|RP| = √[(2-4)² + (-1+5)² + (0-4)²]

= √((-2)² + 4² + (-4)²)

= √36

= 6

|PQ|² + |RP|² = |QR|²

So, triangle is right-angled

8 0
4 years ago
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