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Nostrana [21]
3 years ago
9

Find the zeros of the function !! g(x)=(x-2)(3x+3) lesser x= ? greater x= ?

Mathematics
1 answer:
marin [14]3 years ago
3 0

Answer:

Step-by-step explanation:

Rewrite this function as g(x) = 3(x + 1)(x - 2)

Set each factor equal to zero in turn, solving for x each time:

x + 1 => x = -1  (the lesser zero)

x - 2  =>  x = 2  (the greater zero)

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Shakila paid $130.80 in total.
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The equation y-1=-7(x-3) is written in point-slope form. What is the y-intercept of the line?
vredina [299]

Hello,


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The value of x + y is negative, and x is a positive integer. What must be true about y? Explain.
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Answer:

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5 0
2 years ago
Find the two smallest possible solutions to part 1a​
bixtya [17]
<h3>Answer: A. 5/12, 25/12</h3>

============================

Work Shown:

12*sin(2pi/5*x)+10 = 16

12*sin(2pi/5*x) = 16-10

12*sin(2pi/5*x) = 6

sin(2pi/5*x) = 6/12

sin(2pi/5*x) = 0.5

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2pi/5*x = pi/6+2pi*n or 2pi/5*x = 5pi/6+2pi*n

2/5*x = 1/6+2*n or 2/5*x = 5/6+2*n

x = (5/2)*(1/6+2*n) or x = (5/2)*(5/6+2*n)

x = 5/12+5n or x = 25/12+5n

these equations form the set of all solutions. The n is any integer.

--------

The two smallest positive solutions occur when n = 0, so,

x = 5/12+5n or x = 25/12+5n

x = 5/12+5*0 or x = 25/12+5*0

x = 5/12 or x = 25/12

--------

Plugging either x value into the expression 12*sin(2pi/5*x)+10 should yield 16, which would confirm the two answers.

7 0
3 years ago
Read 2 more answers
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Furkat [3]
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4 0
3 years ago
Read 2 more answers
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