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marin [14]
2 years ago
10

The calories I burn walking can be modeled by the function y = 5x + 100,

Mathematics
1 answer:
Jlenok [28]2 years ago
3 0

Answer:

X=75

Y=5X+100

Y=5*75+100

Y=375+100

Y=475

Therefore, you burnt 475 calories if you walked for 75 minutes

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On a roadtrip, the distance driven can be represented by
Viefleur [7K]
Answer irdk just need points lol.
3 0
3 years ago
594 7/25 +89 37/100=
bonufazy [111]

Hey there!☺

Answer:\boxed{683\frac{13}{20}}

Explanation:

594\frac{7}{25}+89\frac{37}{100}

To solve, we will need to evaluate:

594\frac{7}{25}+89\frac{37}{100}=\frac{13673}{20}

We're not done yet because we need to simplify 13673/20:

\frac{13673}{20}=683\frac{13}{20}

Hope this helps!☺

5 0
3 years ago
Read 2 more answers
Factor 36x^2 + 11x-12 please hurry​
xz_007 [3.2K]

Answer:

The answer is

<h2>(9x - 4)(4x + 3)</h2>

Step-by-step explanation:

36x² + 11x - 12

To factor the expression rewrite 11x as a difference

That's

36x² + 27x - 16x - 12

<u>Factor out 9x from the expression</u>

9x( 4x + 3) - 16x - 12

<u>Factor out - 4 from the expression</u>

9x( 4x + 3) - 4( 4x + 3)

Factor out 4x + 3 from the expression

We have the final answer as

<h3>(9x - 4)(4x + 3)</h3>

Hope this helps you

5 0
3 years ago
Read 2 more answers
The pair of points lies on the same line with the given slope. Find x.
barxatty [35]
Can u answer my question in my profile
7 0
3 years ago
Last month, Katie started training for the swim team. She swam 20 laps every day for 18 training days. This month, Katie wants t
nasty-shy [4]

She swim 20 laps every day for 18 training days

so total laps done last month = 20*18 = 360 laps

She will swim 3 more laps per training day and add more training days to her monthly schedule.

20 laps + 3 laps = 23 laps

(a)If Katie adds 5 training days to her schedule this month, will she swim 215 more laps?

18 days + 5 days more = 23 days

23 laps every day for 23 training days

so total laps = 23*23 = 529 laps. That is 169 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

If Katie adds 10 more training days to her schedule this month, will she swim 215 more laps?

18 days + 10 days more = 28 days

23 laps every day for 28 training days

so total laps = 23*28 =644 laps. That is 284 more laps than 360 laps done last month. Hence she can swim 215 more laps

(c)If Katie adds 6 more training days to her schedule this month, will she swim 215 more laps?

18 days + 6 days more = 24 days

23 laps every day for 24 training days

so total laps = 23*24 =552 laps. That is 192 more laps than 360 laps done last month. Hence she cannot swim 215 more laps

Build an equation for finding the number of additional training days she needs to swim 215 more laps

Let x be the number of days more

So training days = 18 + x

215 more laps , so total laps = 360 + 215 = 575

3 more laps per training day so 20 + 3 = 23 laps per day

laps * training days = total laps

so equation becomes

23 * (18+x) = 575

Now solve for x

414 + 23x = 575

Subtract 414 from both sides

23x = 161

x= 7

so she needs 7 training days to swim 215 more laps

3 0
3 years ago
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