All categories

3 years ago

Work out the length of the following rectangles

Mathematics

1 answer:

tiny-mole [99]3 years ago

8 0

(a) a = 10.9 cm

(b) b = 20.78 cm

(c) c = 4.06 cm

<u>Explanation:</u>

(a)

height, h = 5cm

Hypotenuse, H = 12cm

Base, a = ?

Using pythagoras theorm:

(H)² = (h)² + (a)²

(12)² = (5)² + (a)²

119 = a²

a = 10.9 cm

(b)

Hypotenuse, H = 24 cm

Base, a = 12 cm

Height, b = ?

Using pythagoras theorm:

(H)² = (b)² + (a)²

(24)² = (b)² + (12)²

432 = b²

b = 20.78 cm

(c)

height, h = 4 cm

Hypotenuse, H = 5.7 cm

Base, c = ?

Using pythagoras theorm:

(H)² = (h)² + (c)²

(5.7)² = (4)² + (c)²

16.49 = c²

c = 4.06 cm

You might be interested in

Can someone pleasw helppppppp meee

Sergio [31]

It would be 2,5, and 6. The mode means the number that is repeating the most. Since 2, 5, and 6 all appear 3 times, that is the mode

6 0

3 years ago

Read 2 more answers

Which statements about the graph of the function f(x) = 2x2 – x – 6 are true? Check all that apply.

lbvjy [14]

Hello,

1: dom f=R
2: img f =R
3: 2x²-x-6=2(x²-2x/4+1/46)-6-1/8=2(x-1/4)²-49/8
Vertex=(1/4,-49,8)

4: roots are -3/2 and 2
2(x-1/4)²-49/8=1/8[(4x-1)²-49]=1/8*(4x+6)(4x-8)

5:
From the vertex to ∞
[-1/4 , ∞)

7 0

3 years ago

Because of staffing decisions, managers of the Gibson-Marion Hotel are interested in the variability in the number of rooms occu

olchik [2.2K]

Answer:

a) $s^2 =30^2 =900$

b) $\frac{(19)(30)^2}{30.144} \leq \sigma^2 \leq \frac{(19)(30)^2}{10.117}$

$567.28 \leq \sigma^2 \leq 1690.224$

c) $23.818 \leq \sigma \leq 41.112$

Step-by-step explanation:

Assuming the following question: Because of staffing decisions, managers of the Gibson-Marimont Hotel are interested in the variability in the number of rooms occupied per day during a particular season of the year. A sample of 20 days of operation shows a sample mean of 290 rooms occupied per day and a sample standard deviation of 30 rooms

Part a

For this case the best point of estimate for the population variance would be:

$s^2 =30^2 =900$

Part b

The confidence interval for the population variance is given by the following formula:

$\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}$