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son4ous [18]
3 years ago
7

Choose the function that shows the correct transformation of the quadratic function shifted two units to the right one

Mathematics
1 answer:
MatroZZZ [7]3 years ago
6 0
Answer:
The last one f(x)=(x+2)2+1 because two units to the right is positive and going up is also positive
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Melissa has a choice of two phone plans
harina [27]
What are the plans?
( Sorry if not answering real question.)
4 0
3 years ago
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A typical cell phone plan has a fixed base fee that’s includes a certain amounts of over a charge
Romashka [77]

The answer is 2)C=30+62(g-2)

6 0
3 years ago
A cell phone company charges a flat fee of 20 dollars plus 3 cents a call. What is the total bill if there was a total of 200 ca
34kurt

Answer:

Total Bill = 4006 dollars

Step-by-step explanation:

A cell phone company charges a flat fee of 20 dollars plus 3 cents a call.

If there was a total of 200 calls for the month, the total charge by the cell phone company will be.

Let me convert all to cent first

100 cent = 1 dollar

20 dollar =20 *100

29 dollar = 2000 cent

Charge by the company for a call is 2003 cent

Let me put down the equation.

1 call = 2003 cent

200 calls =( 200 calls* 2003cent)/1 call

200 calls = 200 * 2003cent

200 calls = 400600 cent

Let's convert back to dollar

100 cent = 1 dollar

400600 cent = 400600/100

400600 cent = 4006 dollars

8 0
3 years ago
Simplify the expression. What classification describes the resulting polynomial? (3x^2-11x-4)-(2x^2-x-6)
Gnoma [55]

The expression can be simplified to a polynomial of degree 2.

x^2 - 10x + 2

<h3>How to simplify the expression?</h3>

Here we have the expression:

(3x^2 -11x - 4) - (2x^2 - x - 6)

We can directly simplify this by taking the variable as common factor:

(3 - 2)*x^2 + (-11 + 1)*x + (-4 + 6)\\\\x^2 - 10x + 2

This is a polynomial, as you can see, the maximum exponent is 2, so the degree of the polynomial is 2.

If you want to learn more about polynomials:

brainly.com/question/4142886

#SPJ1

8 0
2 years ago
Can someone tell me how
gulaghasi [49]

the way I get the subsequent term, nevermind the exponents, the exponents part is easy, since one is decreasing and another is increasing, but the coefficient, to get it, what I usually do is.

multiply the current coefficient by the exponent of the first-term, and divide that by the exponent of the second-term + 1.

so if my current expanded term is say 7a³b⁴, to get the next coefficient, what I do is (7*3)/5   <----- notice, current coefficient times 3 divided by 4+1.

anyhow, with that out of the way, lemme proceed in this one.

\bf ~~~~~~~~\textit{binomial theorem expansion} \\\\ \qquad \qquad (1+ax)^n\implies \begin{array}{llll} term&coefficient&value\\ \cline{1-3}&\\ 1&+1&(1)^n(ax)^0\\\\ 2&+\frac{(1)(n)}{1}\to n&(1)^{n-1}(ax)^1\\\\ 3&+\frac{n\cdot (n-1)}{2}&(1)^{n-2}(ax)^2 \end{array}

so, following that to get the next coefficient, we get those equivalents as you see there for the 2nd and 3rd terms.

so then, we know that the expanded 2nd term is 24x therefore

\bf n(1)^{n-1}(ax)1 = 24x\implies n(1)(ax)=24x\implies nax=24x\implies n=\cfrac{24}{a}

we also know that the expanded 3rd term is 240x², therefore we can say that

\bf \cfrac{n(n-1)}{2}~~(1)^{n-2}(ax)^2 = 240x^2\implies \cfrac{n(n-1)}{2}(1)(a^2x^2) = 240x^2 \\\\\\ \cfrac{(n^2-n)(a^2x^2)}{2}=240x^2\implies \cfrac{(n^2-n)(a^2)}{2}=\cfrac{240x^2}{x^2}\implies \cfrac{a^2n^2-a^2n}{2}=240 \\\\\\ a^2n^2-a^2n=480

but but but, we know what "n" equals to, recall above, so let's do some quick substitution

\bf a^2n^2-a^2n=480\qquad \boxed{n=\cfrac{24}{a}}\qquad a^2\left( \cfrac{24}{a} \right)^2-a^2\left( \cfrac{24}{a} \right)=480 \\\\\\ a^2\cdot \cfrac{24^2}{a^2}-24a=480\implies 24^2-24a=480\implies 576-24a=480 \\\\\\ -24a=-96\implies a=\cfrac{-96}{-24}\implies \blacktriangleright a = 4\blacktriangleleft \\\\[-0.35em] ~\dotfill\\\\ n=\cfrac{24}{a}\implies n=\cfrac{24}{4}\implies \blacktriangleright n=6 \blacktriangleleft

7 0
4 years ago
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