8. 1lb 90oz
9.4/5*g=40
We move all terms to the left:
4/5*g-(40)=0
Domain of the equation: 5*g!=0
g!=0/1
g!=0
g∈R
We multiply all the terms by the denominator
-40*5*g+4=0
Wy multiply elements
-200g*g+4=0
Wy multiply elements
-200g^2+4=0
a = -200; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-200)·4
Δ = 3200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
g1=−b−Δ√2a
g2=−b+Δ√2a
The end solution:
Δ−−√=3200−−−−√=1600∗2−−−−−−−√=1600−−−−√∗2√=402√
g1=−b−Δ√2a=−(0)−402√2∗−200=0−402√−400=−402√−400=−2√−10
g2=−b+Δ√2a=−(0)+402√2∗−200=0+402√−400=402√−400=2√−10
10could not figure ten out good luck though youll do great!
