Question

This is my last qestoin.​

Answer 1

Answer:

1.) 1 pound 9 ounces

2.) G= 50

3.) 10/27

Step-by-step explanation:

I hope I helped again! :)

Answer 2

8. 1lb 90oz

9.4/5*g=40

We move all terms to the left:

4/5*g-(40)=0

Domain of the equation: 5*g!=0

g!=0/1

g!=0

g∈R

We multiply all the terms by the denominator

-40*5*g+4=0

Wy multiply elements

-200g*g+4=0

Wy multiply elements

-200g^2+4=0

a = -200; b = 0; c = +4;

Δ = b2-4ac

Δ = 02-4·(-200)·4

Δ = 3200

The delta value is higher than zero, so the equation has two solutions

We use following formulas to calculate our solutions:

g1=−b−Δ√2a

g2=−b+Δ√2a

The end solution:

Δ−−√=3200−−−−√=1600∗2−−−−−−−√=1600−−−−√∗2√=402√

g1=−b−Δ√2a=−(0)−402√2∗−200=0−402√−400=−402√−400=−2√−10

g2=−b+Δ√2a=−(0)+402√2∗−200=0+402√−400=402√−400=2√−10

10could not figure ten out good luck though youll do great!