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Phoenix [80]
3 years ago
11

A train travelled a distance of 6,000km from Lahore to Karachi in 22 hours. And during travel from Karachi to Lahore the train g

ot late due to engine failure and reached Lahore in 28 hours. What is the average speed of train?
180 km/hr
200 km/hr
220 km/hr
240 km/hr
Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0
The average speed of train:
12,000 km / ( 28 + 22 hr) =12,000 km / 50 hr = 240 km/hr
Answer: D)
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237


Step-by-step explanation:


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<h3>Answer:  4</h3>

================================================

Explanation:

We'll only focus on points J and K.

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PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!!
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Answer:

cos(V)=\frac{39}{89}=.44

∠V=64.01°

Step-by-step explanation:

sin(angle)=\frac{opposite}{hypotenuse}

cos(angle)=\frac{adjacent}{hypotenuse}

tan(angle)=\frac{opposite}{adjacent}

  • The cosine of an angle is equal to the side adjacent to the angle over the hypotenuse, the longest side.
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cos(V)=\frac{39}{hypotenuse}

  • We need to find the hypotenuse of this triangle. This is relativly easy to do with a right triangle; we can just use the Pythagorean Theorem.
  • Pythagorean Theorem: a^2+b^2=c^2  where a, b, and c are the 3 different sides of a right triangle.

a^2+b^2=c^2\\(39)^2+(80)^2=c^2\\1521+6400=c^2\\c=\sqrt{7921} \\c=89

  • Our hypotenuse is 89. Now we can finish solving for ∠V.

cos(V)=\frac{39}{89}\\V=cos^-^1(\frac{39}{89})\\

∠V=64.01°

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