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777dan777 [17]
3 years ago
11

110% of what number is 880?

Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0
I would make a proportion out of this to help solve it because I find proportions a bit easier to solve, so the proportion would be: 110/100=880/x

You would just solve it for 800
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8 0
3 years ago
Find the area of an equilateral triangle (regular 3 Gon) with the given measurement 9 in perimeter a=SQ.in
blsea [12.9K]

Answer:

3.897 in^{2}

Step-by-step explanation:

equilateral triangles are also equiangular, meaning the have equal angles.

Triangle sum theory says that angles of a triangle add up to 180.

That means each angle is 60.

A = bh/2

You need the (h). The base of is 3.  Perimeter = 9, so each side is 3

Draw a perpendicular line for the height. The line cuts the base in half (1.5)

Using trigonometry you can find the height.

tan 60° = h/1.5

h = height, 1.5 is half of 3, 60° is the base angle.

multiply each side by 1.5

1.5(tan 60°) = h

h=2.598

then substitute h into formula

A= <u>(2.598)(3) </u>

           2

A = 3.897 rounded

4 0
3 years ago
(05.01)Which equation can be used to calculate the area of the shaded triangle in the figure below?
Lemur [1.5K]
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7 0
3 years ago
Read 2 more answers
How fast is a train going that makes a 330 mile trip in 4 hours.?
maw [93]

Answer:

82.5 miles an hour

330 ÷ 4 = 82.5

Step-by-step explanation:

8 0
3 years ago
Comparing Leaking Pool Problem
Blababa [14]

Answer:

<em>Pool 1 leaks faster than pool 2.</em>

Step-by-step explanation:

<u>Rates of change</u>

The rate of change (ROC) is a measure that compares two quantities, usually to know how fast one variable changes in time.

We are given two rates of change for two pools that are leaking. The first one loses 2/3 gallon in 15 minutes, and the other loses 3/4 gallon in 20 minutes.

To compare them, we are required to express time in hours. Recall one hour has 60 minutes, or equivalently, one minute has 1/60 hours. Converting both times, we have:

15 minutes = 15/60 = 1/4 hours

20 minutes = 20/60 = 1/3 hours

Now compute both rates of change:

Pool 1:

\displaystyle ROC_1=\frac{2/3}{1/4}=\frac{8}{3}\approx 2.67\ gal/h

Pool 2:

\displaystyle ROC_2=\frac{3/4}{1/3}=\frac{9}{4}= 2.25\ gal/h

Comparing both ratios, it's clear pool 1 leaks faster than pool 2.

8 0
3 years ago
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