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alisha [4.7K]
3 years ago
14

Wot it's the missing number x9=6x3

Mathematics
2 answers:
vivado [14]3 years ago
4 0
If i'm understanding this question correctly, i believe that it's 2. 
2*9=6*3
Vedmedyk [2.9K]3 years ago
4 0
x^9=6x^3 :|\text{Solve} 

x^9-6x^3=0 

x^3(x^6-6)=0 

x=0,(+)(-) \sqrt[6]{6}
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galina1969 [7]

Answer:

A. 0.623

Step-by-step explanation:

Hope it helps you in your learning process.

3 0
3 years ago
Read 2 more answers
Please helpppp I’m not sure how to solve
Nesterboy [21]

Answer:

If a is 1.. we substitute one in every a in g(a)

4 * 1 + 16

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f(20)

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Step-by-step explanation:

6 0
3 years ago
Answer the following: a) 2x32 =<br> b) (2 x 3)2 =
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Answer:

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Question 6 (1.25 points)
Lisa [10]

Answer:

Test statistic Z= 1.713

The calculated Z- value =  1.7130 < 2.576 at 0.01 level of significance

Null hypothesis is accepted

There is no difference between the  mean annual salary of all lawyers in a city is  different from $110,000

Step-by-step explanation:

<u><em>Step(i):-</em></u>

A researcher wants to test if the mean annual salary of all lawyers in a city is

different from $110,000

Mean of the Population  μ = $110,000

Sample size 'n' = 53

Mean of the sample x⁻ = $114,000.

standard deviation of the Population = $17,000,

Level of significance = 0.01

Null hypothesis :

There is no difference between the  mean annual salary of all lawyers in a city is  different from $110,000

H₀:  x⁻ =  μ

Alternative Hypothesis :  x⁻ ≠  μ

<u><em>Step(ii)</em></u>:-

Test statistic

                 Z = \frac{x^{-}-mean }{\frac{S.D}{\sqrt{n} } }

                 Z = \frac{114000-110000}{\frac{17000}{\sqrt{53} } }

                Z =  1.7130

Tabulated value Z = 2.576 at 0.01 level of significance

The calculated Z- value =  1.7130 < 2.576 at 0.01 level of significance

Null hypothesis is accepted

There is no difference between the  mean annual salary of all lawyers in a city is  different from $110,000

4 0
3 years ago
Simplify (3×22)÷6+(28-(4)2=
polet [3.4K]
(3*22)divide 6 + (28-(4)2=
31
5 0
3 years ago
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